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3 years ago

61 pts!!!!!!!!!!!!!!!!!!!

2 answers:

8 0

1. polygon-Any closed figure bounded by three or more segments that only intersect at their endpoints. The segments are called the sides, and the endpoints are called the vertices of the polygon.

2. consecutive vertices- A polygon with all the angles equal and all the sides equal.

3. consecutive sides- Any two sides of a polygon that have a common endpoint.

4. diagonal of a polygon- A segment joining two nonconsecutive vertices.

5. regular polygon- A polygon with all the angles equal and all the sides equal.

Olegator [25]3 years ago

3 0

A plane figure with at least three straight sides and angles, and typically five or more.Polygon-

Consecutive vertices-The endpoints of one side of a polygon.

diagonal of a polygon A polygon with all the angles equal and all the sides equal. regular polygon Any closed figure bounded by three or more segments that only intersect at their endpoints. The segments are called the sides, and the endpoints are called the vertices of the polygon. Plz mark me brainliest! Hope this helps!

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How do different lense types connect to helping locate sharks through mechanical radio waves?

Gnom [1K]

Answer:

I am not quite sure, but maybe you can find something from these websites

The second one to me is the best. Sorry if it wasn't what you needed. :(

Explanation:

https://phys.org/news/2012-11-metamaterial-lens-focuses-radio-device.html

https://animals.howstuffworks.com/fish/sharks/shark-yummy-hum1.htm

5 0

3 years ago

What is the magnitude of vector K ?

vovangra [49]

Answer:

Vector K = 8 m

Explanation:

The given figure shows a right angle triangle JKL. It is given that :

vector L = 10 m

vector J = 6 m

We have to find vector k. We can find it by using Pythagoras theorem. According to this theorem, the sum of squares of perpendicular and the base is equal to the square of the longest side.

$L^2=K^2+J^2$

$K^2=L^2-J^2$

$K^2=(100)^2-(6)^2$

K = 8 m

Hence, the magnitude of vector K is 8 m.

3 0

3 years ago

How does inertia affect the motion of an object?

Furkat [3]

Inertia affects the motion of an object as follows:

When an object is in motion, it will continue to be in the same state unless otherwise some outside force is being applied to it. Thus, inertia affects the motion of an object. It restricts some other force being acted upon the object.

But mass of an object is directly proportional to inertia. So when the inertia is more on an object, it means that the object has more mass. For example, if there are two similar bricks, one that is made up of mortar and the other one is made of Styrofoam.

To identify which brick is made of Styrofoam without lifting the bricks, push both the bricks with equal force, the one that has less resistance tends to move faster. This means that it has less inertia and hence less mass.

4 0

3 years ago

Cause and Effect: What would happen to a space vehicle in orbit around Earth if it sped up?

gulaghasi [49]

Answer:

G M m / R^2 = m v^2 / R gravitational force = centripetal force

G M = v^2 R = constant

As v increases R will must decrease

Take the moon as an example

S = 2 pi R where R is about 240,000 miles for one orbit

S / 1 day = 54,000 miles/day for a 28 day circuit

S / 1 hr = 54000 / 24 = 2200 mph which is much less than a satellite in orbit

4 0

2 years ago

During each heartbeat, about 80 g of blood is pumped into the aorta inapproximately 0.2 s. During this time, the blood is accele

taurus [48]

Answer:

Work is done by the heart on the blood during this time is 0.04 J

Explanation:

Given :

Mass of blood pumped, m = 80 g = 0.08 kg

Initial speed of the blood, u = 0 m/s

Final speed of the blood, v = 1 m/s

Initial kinetic energy of blood is determine by the relation:

$E_{1}=\frac{1}{2} m u^{2}$

Final kinetic energy of blood is determine by the relation:

$E_{2}=\frac{1}{2} m v^{2}$

Applying work-energy theorem,

Work done = Change in kinetic energy

W = E₂ - E₁

$W=\frac{1}{2} m (v^{2}-u^{2})$

Substitute the suitable values in the above equation.

$W=\frac{1}{2}\times0.08\times (1^{2}-0^{2})$

W = 0.04 J

6 0

3 years ago