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gogolik [260]
4 years ago
14

For a current to flow continuously through a circuit, the circuit must be:

Physics
1 answer:
BabaBlast [244]4 years ago
8 0

Answer:

An electrical current is an electrical charge flowing around a circuit. Carried by billions of tiny particles called electrons, the charge is already in the wires.

Explanation:

There are three basic conditions for the electric current flow is to be given below:-

  • The loop must be shuttered where current throws occur.
  • There must be some possible distinctions in the chain.
  • The medium in which current flows will be a conductor (but flow in the semiconductor at a higher temp. current).

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The Supernova will be observed on Earth 60,000 years from now.

<h3>What is Supernova?</h3>
  • A supernova is a star's tremendous and brilliant explosion. It is referred to as a supernova or a supernovae and is abbreviated as SN or SNe.
  • This fleeting astronomical occurrence takes place either when a white dwarf is set off into uncontrolled nuclear fusion or during the latter phases of the development of a big star. The original object, known as the progenitor, either disintegrates completely or falls into a neutron star or black hole.
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6 0
2 years ago
The world’s supply of fossil fuels will _____.
Mekhanik [1.2K]

The world’s supply of fossil fuels will dwindle slowly until a replacement source is found that provides the same power.

bc some day we will actually run out of it and find sth that gives power

3 0
3 years ago
Read 2 more answers
In some applications of ultrasound, such as its use on cranial tissues, large reflections from the surrounding bones can produce
worty [1.4K]

Answer:

b. 0.75 mm

Explanation:

The distance between antinodes d is half the wavelength \lambda. We can obtain the wavelength with the formula v=\lambda f, where f is the frequency given (f=1MHz=1\times10^6Hz) and v is the speed of sound in body tissues (v=1540m/s), so putting all together we have:

d=\frac{\lambda}{2}=\frac{v}{2f}=\frac{1540m/s}{2(1\times10^6Hz)}=0.00077m=0.77mm

which is very close to the 0.75mm option.

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Algorithm to determine number of shortest paths between two nodes
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