i dont get it so much but
The weight of the bag pack is 8.2 N. g = 1.64 m/s2. Hence, the acceleration due to gravity on moon is 1.64 m/s2. sooo? is it right
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<h3><u>
For the aceleration:</u></h3>
First, let's find the resultant, and <u>applicate 2nd law of Newton</u> using the resultant, so:
R = ma
F - Ff = ma
Data:
F = Force = 1150 N
Ff = Friction force = 490 N
m = Mass = 150 kg
a = Aceleraction = ?
Replacing according our data:
1150 N - 490 N = 150 kg * a
660 N = 150 kg * a
660 N / 150 kg = a
a = 4,4 m/s² ← Aceleration of the object
<h3><u>For the normal force:</u></h3>
The normal force IS NOT the resultant force, the normal force's the force between the ground and the object, in another words, is the weight of the object, and for the weight:
w = mg
w = 150 kg * 10 m/s²
w = 1500 N ← Normal force between object and ground.
Answer:
When he weight of the car is 8.55 x
N then power = 314.012 KW
When he weight of the car is 1.10 x
N then power = 43.76 KW
Explanation:
Given that
Initial velocity
= 0
Final velocity
= 24.8 
Time = 7.88 sec
We know that power required to accelerate the car is given by
P = 
Change in kinetic energy Δ K.E = 
Since Initial velocity
= 0
⇒ Δ K.E = 
⇒ Power P = 
⇒ Power P =
-------- (1)
(a). The weight of the car is 8.55 x
N = 8550 N
Put all the values in above formula
So power P = 
P = 314.012 KW
(b). The weight of the car is 1.10 x
N = 11000 N
Put all the values in equation (1) we get
P = 
P = 43.76 KW