All categories

3 years ago

The sum of two numbers is 17 and their differences is 29. What are the two numbers?

Mathematics

2 answers:

aksik [14]3 years ago

8 0

Answer:

x + y = 17

x - y = 29

x = 17 - y

x - y = 29

x = 17 - y

17 - y - y = 29

x = 17 - y

17 - 2y = 29

x = 17 - y

- 2y = 29 - 17

x = 17 - y

-2y = 12

x = 17 - y

y = -6

x = 17 - (-6)

y = -6

x = 17 + 6

y = -6

x = 23

y = -6

Read more on Brainly.com - brainly.com/question/14264#readmore

Step-by-step explanation:

vaieri [72.5K]3 years ago

6 0

X + y = 17
x - y = 29

x = 17 - y
x - y = 29

x = 17 - y
17 - y - y = 29

x = 17 - y
17 - 2y = 29

x = 17 - y
- 2y = 29 - 17

x = 17 - y
-2y = 12

x = 17 - y
y = -6

x = 17 - (-6)
y = -6

x = 17 + 6
y = -6

x = 23
y = -6

You might be interested in

IS MY ANSWER CORRECT??? If not what’s the correct answer

Kazeer [188]

Answer:

yes

Step-by-step explanation:

your answer is correct

4 0

3 years ago

Read 2 more answers

Please answer this correctly without making mistakes

boyakko [2]

Answer:

105/4 or 26.25 mi

Step-by-step explanation:

hillsdale to fairfax 8 7/8 = 71/8

fairfax to yardley = 17 3/8 = 139/8

71/8 + 139/8 = 105/4 or 26 2/8

7 0

3 years ago

Lewis walked 9/10 of a mile. His friend walked 2/5 of the way with him. How many miles did Lewis's friend walk with him?

iVinArrow [24]

Answer:

Lewis's friend walked with him 9/25 miles

Step-by-step explanation:

Given that

Lewis walked 9/10 of a mile

And His friend accompanied him on 2/5 of the way.

This is a simple question of fraction multiplication

The fraction 2/5 has to multiplied with the miles walked by lewis

$= \frac{2}{5} * \frac{9}{10}\\=\frac{9}{25}$

Hence,

Lewis's friend walked with him 9/25 miles

5 0

3 years ago

Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

5 0

3 years ago

If 10 tickets to the movies cost $55, how much would 4 tickets cost?

11111nata11111 [884]

Answer:

$55 \div 10 = \: 5.5 \: dollars \\ 5.5 \times 4 = 22.0 \: dollars$

5 0

3 years ago