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Law Incorporation [45]
3 years ago
6

For the following reaction, calculate how many moles of NO2 forms when 0.356 moles of the reactant completely reacts.

Chemistry
1 answer:
Nesterboy [21]3 years ago
7 0

Answer:

0.712 mol of NO₂ are formed .

Explanation:

For the reaction , given in the question ,

2 N₂O₅ ( g )  →  4 NO₂ ( g ) + O₂ ( g )

From the above balanced reaction ,

2 mol of N₂O₅  reacts to give 4 mol of NO₂

Applying unitary method ,

1 mol of N₂O₅  reacts to give 4 / 2 mol of NO₂

From the question , 0.356 mol of N₂O₅ are reacted ,

<u>now, using the above equation , to calculate the moles of the NO₂ , as follow -</u>

Since ,

1 mol of N₂O₅  reacts to give 4 / 2 mol of NO₂

0.356 mol of N₂O₅  reacts to give 4 / 2 * 0.356 mol of NO₂

Calculating ,

0.712 mol of NO₂ are formed .

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A 0.150 M sodium chloride solution is referred to as a physiological saline solution because it has the same concentration of sa
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<h3>Answer:</h3>

2.41 g NaCl

<h3>Explanation:</h3>

We are given the;

Molarity of NaCl = 0.150 M

Volume of the solution = 275.0 mL

We are required to calculate the mass of NaCl solute;

<h3>Step 1: Number of moles of NaCl solute </h3>

Moles are calculated by;

Moles = Molarity × Volume

Therefore;

Number of moles of NaCl = 0.150 M × 0.275 L

                                           = 0.04125 moles

<h3>Step 2: Mass of NaCl solute </h3>

Mass of the compound is given by multiplying the number of moles by the molar mass of the compound.

Molar mass of NaCl = 58.44 g/mol

Therefore;

Mass of NaCl = 0.04125 moles × 58.44 g/mol

                       = 2.41 g

Thus, the mass of NaCl solute is 2.41 g

7 0
3 years ago
If your client receives a letter from SilverScript requesting proof of Creditable Coverage, and the client has already submitted
KatRina [158]

If your client receives a letter from SilverScript requesting proof of Creditable Coverage, they can ignore the letter is a false statement

<h3>What is Creditable coverage?</h3>

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Note that  the types of creditable coverage plans are group and individual health plans, student health plans,  and others.

It is not right to ignore any letter sent to you concerning the case above as it may be vital and as such, the statement of If your client receives a letter from SilverScript requesting proof of Creditable Coverage, and the client has already submitted proof of creditable coverage with the enrollment application, they can ignore the letter is a wrong/false statement.

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2 years ago
Compared with gases, liquids: A. have stronger intermolecular attractions. B. have more space between their particles. C. are mu
Fiesta28 [93]
A. have stronger intermolecular attractions.
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2 years ago
What volume of Co2 (carbon (iv) oxide)
hram777 [196]

Answer:

2.1056L or 2105.6mL

Explanation:

We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:

Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol

Mass of Na2CO3 = 10g

Mole of Na2CO3 =.?

Mole = mass /molar mass

Mole of Na2CO3 = 10/106

Mole of Na2CO3 = 0.094 mole

Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:

Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

From the balanced equation above,

1 mole of Na2CO3 reacted to produce 1 mole of CO2.

Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.

Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:

1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.

Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L

Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL

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Because of bronze'z high _________ , ancient Egyptians were able to use it to make mirrors
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Shiny and soft mental
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