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Law Incorporation [45]
3 years ago
6

For the following reaction, calculate how many moles of NO2 forms when 0.356 moles of the reactant completely reacts.

Chemistry
1 answer:
Nesterboy [21]3 years ago
7 0

Answer:

0.712 mol of NO₂ are formed .

Explanation:

For the reaction , given in the question ,

2 N₂O₅ ( g )  →  4 NO₂ ( g ) + O₂ ( g )

From the above balanced reaction ,

2 mol of N₂O₅  reacts to give 4 mol of NO₂

Applying unitary method ,

1 mol of N₂O₅  reacts to give 4 / 2 mol of NO₂

From the question , 0.356 mol of N₂O₅ are reacted ,

<u>now, using the above equation , to calculate the moles of the NO₂ , as follow -</u>

Since ,

1 mol of N₂O₅  reacts to give 4 / 2 mol of NO₂

0.356 mol of N₂O₅  reacts to give 4 / 2 * 0.356 mol of NO₂

Calculating ,

0.712 mol of NO₂ are formed .

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