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Hoochie [10]
3 years ago
5

Based on how solar radiation received varies with latitude, it can be inferred that seasonal temperature contrasts would _______

_ as latitude increases
Physics
2 answers:
Andrei [34K]3 years ago
4 0

Answer:

Increase

Explanation:

As the latitude increases, the angle at which the Sun light falls on the Earth changes. This is known as the Sun angle. Although the rays fall on the Earth parallely but they make different angles with objects at different latitudes due to Earth's curvature.

We know that the throughout the year the Sun moves in the sky and changes its altitude but it never gets overhead for a latitude above or below the tropics. Due to this phenomenon, the Sun angle doesn't vary much for tropical region whereas it varies a lot for the region beyond tropics. If the Sun angle varies too much the contrast between the seasonal temperature also increases.

For example: the Sun angle for equator lies in the range of 0° - 23.5° while at the arctic circle (66.5° N) the range is 43° - 90°.

Klio2033 [76]3 years ago
3 0
The answer that best completes the statement above is the word INCREASE. Therefore, the <span>seasonal temperature contrasts would INCREASE as latitude increases. The existence of varied seasonal temperature is dependent on the latitude on earth depending on the location. Hope this answers your question.</span>
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A wave has a length of 8 meters and a speed of 32 meters per second. What is the frequency of the wave
Naddika [18.5K]

Answer:

The frequency of wave is 4 hertz.

Explanation:

Given,

wave length = 8m

speed of sound ( v) = 32 m/s

frequency ( f) = ?

we know,

v = f × lambda

or, 32 = f × 8

or, f = 32/8

or, f = 4 Hertz.

5 0
3 years ago
The tension in the rope securing the upper pulley and the force that must be applied to keep the system in equilibrium ​
chubhunter [2.5K]

Answer:

Explanation:

In a frictionless system with no acceleration, the tension in the rope must be F along its entire length

FBD analysis of the lower pulley has two upward acting tension vectors F and one downward acting weight vector W

2F = W

F = W/2

FBD analysis of the upper pulley has one upward acting support vector T and three downward acting tension vectors F

T = 3F

T = 3(W/2)

T = 1.5W

8 0
2 years ago
A certain parallel-plate capacitor is filled with a dielectric for which κ = 6.56. The area of each plate is 0.0830 m2, and the
mafiozo [28]

Answer:

4.86\times 10^{-7}\ J

Explanation:

Given:

Dielectric of the medium between the plates (k) = 6.56

Area of eac plate (A) = 0.0830 m²

Separation between the plates (d) = 1.95 mm = 0.00195 m [1 mm = 0.001 m]

Maximum electric field (E_{max}) = 202 kN/C = 202000 N/C [1 kN = 1000 N]

Permittivity of space (ε₀) = 8.854 × 10⁻¹² F/m

The maximum potential difference across the plates of the capacitor is given as:

V_{max}=E_{max}d\\\\V=(202000\ N/C)(0.00195\ m)\\\\V=393.9\ V

Now, capacitance of the capacitor is given as:

C=\dfrac{k\epsilon_0A}{d}\\\\C=\frac{6.56\times 8.854\times 10^{-12}\ F/m\times 0.0830\ m^2}{0.00195\ m}\\\\C=2.47\times 10^{-9}\ F

The maximum energy stored in the capacitor is given as:

U_{max}=\frac{1}{2}CV_{max}^2\\\\U_{max}=\frac{1}{2}\times (2.47\times 10^{-9}\ F)\times  393.9\ V\\\\U_{max}=4.86\times 10^{-7}\ J

Therefore, the maximum energy that can be stored in the capacitor is 4.86\times 10^{-7}\ J

6 0
2 years ago
If a motorbike of mass 150 kg moving with the speed of 36 km/hr produces
Aloiza [94]

Answer:

P = 7500 [W]

Explanation:

First We must use Newton's second law to find the force. Newton's Second Law tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

m = mass = 150 [kg]

a = acceleration = 5 [m/s²]

F = 150*5\\F = 750 [N]

We know that the work is determined by multiplying the force by the distance, in this way the units of the work are [N*m] which corresponds to 1 Joule [J].

And the power is determined by dividing the work by the time, in this way we have that [J/s] corresponds to 1 [W].

We must convert the speed from kilometers per hour to meters per second.

36[km/hr]*1000[\frac{m}{1km}]*[\frac{1hr}{3600s} ]=10 [m/s]

P=F*v

where:

P = power [W]

F = force = 750 [N]

v = 10 [m/s]

P = 750*10\\P = 7500 [W]

8 0
2 years ago
Cart A is pulled with a 2 Newton force for 2
nata0808 [166]

The cart A experienced the greatest impulse.

The given parameters;

  • force exerted on Cart A = 2 N
  • time of force action on cart A = 2 s
  • force exerted on cart B = 1
  • time of force action on cart B = 3 s

Impulse is defined as the product of the applied force  and time of action of the applied force.

J = Ft

where;

J is the impulse

F is the applied force

t is the time of action

The impulse experienced by cart A;

J = 2 x 2 = 4 Ns

The impulse experienced by cart B;

J = 1 x 3 = 3 Ns

Thus, the cart A experienced the greatest impulse.

Learn more here: brainly.com/question/21353069

4 0
2 years ago
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