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Hoochie [10]
3 years ago
5

Based on how solar radiation received varies with latitude, it can be inferred that seasonal temperature contrasts would _______

_ as latitude increases
Physics
2 answers:
Andrei [34K]3 years ago
4 0

Answer:

Increase

Explanation:

As the latitude increases, the angle at which the Sun light falls on the Earth changes. This is known as the Sun angle. Although the rays fall on the Earth parallely but they make different angles with objects at different latitudes due to Earth's curvature.

We know that the throughout the year the Sun moves in the sky and changes its altitude but it never gets overhead for a latitude above or below the tropics. Due to this phenomenon, the Sun angle doesn't vary much for tropical region whereas it varies a lot for the region beyond tropics. If the Sun angle varies too much the contrast between the seasonal temperature also increases.

For example: the Sun angle for equator lies in the range of 0° - 23.5° while at the arctic circle (66.5° N) the range is 43° - 90°.

Klio2033 [76]3 years ago
3 0
The answer that best completes the statement above is the word INCREASE. Therefore, the <span>seasonal temperature contrasts would INCREASE as latitude increases. The existence of varied seasonal temperature is dependent on the latitude on earth depending on the location. Hope this answers your question.</span>
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VARVARA [1.3K]

Answer:

the correct one is D,  

Ultraviolet, x-ray, gamma ray

Explanation:

Electromagnetism radiation are waves of energy that is expressed by the Planck relationship

          E = h f

where h is the plank constant and f the frequency of the radiation.

Also the speed of light is

          c = λ f

         

we substitute

          E = h c /λ

therefore to damage the cells of the body radiation of appreciable energy is needed

microwave radiation has an energy of 10⁻⁵ eV

infrared radiation                E = 10⁻² eV

visible radiation                   E = 1 to 3 eV

radiation Uv                         E = 3 to 6 eV

X-ray                                    E = 10 eV

 

gamma rays                         E = 10 5 eV

therefore we see that the high energy radiation is gamma rays, x-rays and ultraviolet light.

When checking the answers, the correct one is D

6 0
2 years ago
True or False: The arrows on a motion map should point in the directions of motion.
slavikrds [6]

Answer:

true,true,false

Explanation:

its false because if it is equal it would show an arrow pointing left and a 20 and the same for the right

3 0
3 years ago
Convert 10095 mm to pm​
ludmilkaskok [199]

Answer:

1.01 × 1013 picometres

Explanation:

multiply the length value by 1e+9

3 0
3 years ago
Water (density = 1x10^3 kg/m^3) flows at 15.5 m/s through a pipe with radius 0.040 m. The pipe goes up to the second floor of th
RUDIKE [14]

Answer:

The speed of the water flow in the pipe on the second floor is approximately 13.1 meters per second.

Explanation:

By assuming that fluid is incompressible and there are no heat and work interaction through the line of current corresponding to the pipe, we can calculate the speed of the water floor in the pipe on the second floor by Bernoulli's Principle, whose model is:

P_{1} + \frac{\rho\cdot v_{1}^{2}}{2}+\rho\cdot g\cdot z_{1} = P_{2} + \frac{\rho\cdot v_{2}^{2}}{2}+\rho\cdot g\cdot z_{2} (1)

Where:

P_{1}, P_{2} - Pressures of the water on the first and second floors, measured in pascals.

\rho - Density of water, measured in kilograms per cubic meter.

v_{1}, v_{2} - Speed of the water on the first and second floors, measured in meters per second.

z_{1}, z_{2} - Heights of the water on the first and second floors, measured in meters.

Now we clear the final speed of the water flow:

\frac{\rho\cdot v_{2}^{2}}{2} = P_{1}-P_{2}+\rho \cdot \left[\frac{v_{1}^{2}}{2}+g\cdot (z_{1}-z_{2}) \right]

\rho\cdot v_{2}^{2} = 2\cdot (P_{1}-P_{2})+\rho\cdot [v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2})]

v_{2}^{2}= \frac{2\cdot (P_{1}-P_{2})}{\rho}+v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2})

v_{2} = \sqrt{\frac{2\cdot (P_{1}-P_{2})}{\rho}+v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2}) } (2)

If we know that P_{1}-P_{2} = 0\,Pa, \rho=1000\,\frac{kg}{m^{3}}, v_{1} = 15.5\,\frac{m}{s}, g = 9.807\,\frac{m}{s^{2}} and z_{1}-z_{2} = -3.5\,m, then the speed of the water flow in the pipe on the second floor is:

v_{2}=\sqrt{\left(15.5\,\frac{m}{s} \right)^{2}+2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (-3.5\,m)}

v_{2} \approx 13.100\,\frac{m}{s}

The speed of the water flow in the pipe on the second floor is approximately 13.1 meters per second.

4 0
3 years ago
How does the law of conservation of mass apply to this reaction: Al + 3HCl → H2 + AlCl3 ?
11Alexandr11 [23.1K]

Answer:

Only the hydrogen needs to be balanced. There are equal numbers of aluminum and chlorine.

Explanation:

I took the K12 test, listened to some other idiot and got it wrong, so this is the correct one.

Hope this helps!

8 0
3 years ago
Read 2 more answers
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