Answer:
The frequency of wave is 4 hertz.
Explanation:
Given,
wave length = 8m
speed of sound ( v) = 32 m/s
frequency ( f) = ?
we know,
v = f × lambda
or, 32 = f × 8
or, f = 32/8
or, f = 4 Hertz.
Answer:
Explanation:
In a frictionless system with no acceleration, the tension in the rope must be F along its entire length
FBD analysis of the lower pulley has two upward acting tension vectors F and one downward acting weight vector W
2F = W
F = W/2
FBD analysis of the upper pulley has one upward acting support vector T and three downward acting tension vectors F
T = 3F
T = 3(W/2)
T = 1.5W
Answer:

Explanation:
Given:
Dielectric of the medium between the plates (k) = 6.56
Area of eac plate (A) = 0.0830 m²
Separation between the plates (d) = 1.95 mm = 0.00195 m [1 mm = 0.001 m]
Maximum electric field
= 202 kN/C = 202000 N/C [1 kN = 1000 N]
Permittivity of space (ε₀) = 8.854 × 10⁻¹² F/m
The maximum potential difference across the plates of the capacitor is given as:

Now, capacitance of the capacitor is given as:

The maximum energy stored in the capacitor is given as:

Therefore, the maximum energy that can be stored in the capacitor is 
Answer:
P = 7500 [W]
Explanation:
First We must use Newton's second law to find the force. Newton's Second Law tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
m = mass = 150 [kg]
a = acceleration = 5 [m/s²]
![F = 150*5\\F = 750 [N]](https://tex.z-dn.net/?f=F%20%3D%20150%2A5%5C%5CF%20%3D%20750%20%5BN%5D)
We know that the work is determined by multiplying the force by the distance, in this way the units of the work are [N*m] which corresponds to 1 Joule [J].
And the power is determined by dividing the work by the time, in this way we have that [J/s] corresponds to 1 [W].
We must convert the speed from kilometers per hour to meters per second.
![36[km/hr]*1000[\frac{m}{1km}]*[\frac{1hr}{3600s} ]=10 [m/s]](https://tex.z-dn.net/?f=36%5Bkm%2Fhr%5D%2A1000%5B%5Cfrac%7Bm%7D%7B1km%7D%5D%2A%5B%5Cfrac%7B1hr%7D%7B3600s%7D%20%5D%3D10%20%5Bm%2Fs%5D)

where:
P = power [W]
F = force = 750 [N]
v = 10 [m/s]
![P = 750*10\\P = 7500 [W]](https://tex.z-dn.net/?f=P%20%3D%20750%2A10%5C%5CP%20%3D%207500%20%5BW%5D)
The cart A experienced the greatest impulse.
The given parameters;
- force exerted on Cart A = 2 N
- time of force action on cart A = 2 s
- force exerted on cart B = 1
- time of force action on cart B = 3 s
Impulse is defined as the product of the applied force and time of action of the applied force.
J = Ft
where;
J is the impulse
F is the applied force
t is the time of action
The impulse experienced by cart A;
J = 2 x 2 = 4 Ns
The impulse experienced by cart B;
J = 1 x 3 = 3 Ns
Thus, the cart A experienced the greatest impulse.
Learn more here: brainly.com/question/21353069