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3 years ago

By what factor would your weight be multiplied if the earth were1/2 as massavise and the diameter was unchanged

1 answer:

Nutka1998 [239]3 years ago

4 0

Let F be the force of gravity, G be the gravitational constant, M be the mass of the earth, m your mass and r the radius of the earth, then:

F = G(Mm / (4(pi)*r^2))

The above expression gives the force that you feel on the earth's surface, as it is today!

Let us now double the mass of the earth and decrease its diameter to half its original size.

This is the same as replacing M with 2M and r with r/2.

Now the gravitational force (F' ) on the new earth's surface is given by:

F' = G(2Mm / (4(pi)(r/2)^2)) = 2G(Mm / ((1/4)*4(pi)*r^2)) = 8G(Mm / (4(pi)*r^2)) = 8F

So:

F' = 8F

This implies that the force that you would feel pulling you down (your weight) would increase by 800%!

You would be 8 times heavier on this "new" earth!

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A positive charge is moved from one point to another point along an equipotential surface. The work required to move the charge

Strike441 [17]

Answer:zero

Explanation:

Work done in moving a charge is zero in equipotential surface because potential of each point is same .

When there is Potential gradient then some particle experiences a force while moving but in equipotential surface there is no potential gradient , that is why work done in moving a charge is zero.

5 0

3 years ago

The slope at point A of the graph given below is: WILL MARK BRAINLIEST TO CORRECT ANSWER

steposvetlana [31]

RQ/PQ I think

rise/run

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3 years ago

An object moves in a straight path. Its position x as a function of time t is presented by the equation x(t) = at – bt2+c, where

ankoles [38]

Answer:

The answer is below

Explanation:

Given that:

x(t) = at – bt2+c

a) x(t) = at – bt2+c

Substituting a = 1.4 m/s, b = 0.06 m/s2 and c =50 m gives:

x(t) = 1.4t - 0.06t² + 50

At t = 5, x(5) = 1.4(5) - 0.06(5)² + 50 = 55.5 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

$v=\frac{x(5)-x(0)}{5-0}\\ \\v=\frac{55.5-50}{5-0}=1.1\\ \\v=1.1\ m/s$

b) x(t) = 1.4t - 0.06t² + 50

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

$v=\frac{x(10)-x(0)}{10-0}\\ \\v=\frac{58-50}{10-0}=0.8\\ \\v=0.8\ m/s$

c) x(t) = 1.4t - 0.06t² + 50

At t = 15, x(5) = 1.4(15) - 0.06(15)² + 50 = 57.5 m

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

The average velocity (v) is given as:

$v=\frac{x(15)-x(10)}{15-10}\\ \\v=\frac{57.5-58}{15-10}=0.1\\ \\v=0.1\ m/s$

6 0

3 years ago

What three categories can every living thing in a forest ecosystem be sorted into

juin [17]

Answer:

Producers

Consumers

Decomposers

Explanation:

The three categories in which every living thing in a forest ecosystem can be sorted into are producers, consumers and decomposers.

The producers as the name implies manufactures food for the whole of the ecosystem. They take inorganic materials from the environment and convert them into useful food materials. All plants are producers and some micro-organisms.

Animals are consumers and they take up the produced food for their own nourishment and life activities.

Decomposers recycles materials in the ecosystem by converting wastes generated by producers and consumers into useful products that returns to the atmosphere or replenishes soil nutrients.

4 0

4 years ago

Which of the following is a chemical property of a mineral?

zzz [600]

Hardness, color , and luster.

But since you can pick one, I would say hardness

6 0

3 years ago

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