Answer:
What is the difference between quantum or nuclear physics?
How can I get the most out of Crunchbase Pro?
"Quantum physics" is an umbrella term for any field which uses the quantum formulation of the universe - I.e the postulate that observables are well defined as the eigenstates of Hermitian Operators, and all state wavefunctions obey the Schrödinger equation.
Basically all modern science uses quantum mechanics to a degree - astronomy needs it to predict the behaviour of white dwarfs, condensed matter for semiconductor behaviour and so on.
Nuclear physics is a field focussing on the internal structure and interactions of the nucleus. It lies well within the range of the quantum domain, and is 100% reliant on quantum physics to make any sensible predictions. Nuclear physics also has significant crossover with "particle physics", such that the two are quite often used interchangeably.
Nuclear Physics on the other hand, concerns itself with the particles of the nucleus called nucleons (protons & neutrons). ... In the nucleus the leading theory is quantum chromodynamics (QCD) which attempts to explain phenomena in terms of quarks which are the particles that are proposed to make up the nucleons.
Answer:
Explanation:
initial velocity, u = 0 m/s
time, t = 8.99 s
final velocity, v = 21.9 m/s
diameter of tyre, D = 57.5 cm
(a) Let a is the acceleration, and n be the number f revolutions made by the tyre.
Use first equation of motion
v = u + at
21.9 = 0 + a x 8.99
a = 2.44 m/s²
Use third equation of motion
v² = u² + 2 a s
21.9 x 21.9 = 0 + 2 x 2.44 x s
s = 98.28 m
Circumference of wheel, S = π x D = 3.14 x 0.575 = 1.8055 m
number of revolutions, n = distance / circumference
n = 98.28 / 1.8055
n = 54.4
Cancer-causing agents are also called <span>carcinogens</span>
The basic relationship between frequency of an electromagnetic wave and wavelength of the wave is
where
is the speed of light.
Manipulating the equation, we can rewrite it as
The frequency of the wave in our problem is
so if we use the previous formula, we find the correspondant wavelength:
