Answer:
6
Explanation:
FCC is face centered cubic lattice. In FCC structure, there are eight atoms at the eight corner of the cubic unit cell and one atom centered in each of the faces. FCC unit cells consist of four atoms, (8/8) at the corners and (6/2) in the faces.
Given that, Cu has FCC structure and it contains a vacancy at origin (0, 0, 0). And there is no other vacancy directly adjacent to the vacancy at the origin. So, all the adjacent positions contain Cu atoms. Hence, the total number of adjacent atoms of the vacancy at origin can jump into this vacancy.
the above FCC unit cell clearly indicates that there are six adjacent atoms adjacent to the vacancy at origin
So, the total number of adjacent atoms of the vacancy at origin can jump into this vacancy is 6.
Answer:
28.43 min
Explanation:
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given that:
The rate constant, k = min⁻¹
Initial concentration = 0.1 M
Final concentration = M
Time = ?
Applying in the above equation, we get that:-
Answer:
physical- torn paper, coloring leaves in a coloring book
chemical- burned paper, leaves turning colors during fall and winter
Explanation:
The average rate of formation of O2 is 4.225 × 10-4 M min-1
<h3>What is the equation of the reaction?</h3>
The equation of the reaction is given below:
From the equation of the reaction, 2 moles of Ibuprofen pentoxide decomposes to produce 1 mole of oxygen.
<h3>What is the average rate of formation of 02?</h3>
Rate of reaction is given as:
- Moles of product formed/moles of reactants used up/ time
- The ratio of mole of dinitrogen pentoxide decomposed to moles of oxygen produced is 2:1
Rate of disappearance of N2O5 = 8.45×10-4 M min-1.
Therefore, average rate of formation of O2 = 1/2 × 8.45×10-4 M min-1
Average rate of formation of O2 = 4.225 × 10-4 M min-1
Therefore, the average rate of formation of O2 is 4.225 × 10-4 M min-1
Learn more about rate of reaction at: brainly.com/question/24795637