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Novosadov [1.4K]
3 years ago
5

For each of the following ionic bonding examples, show the transfer of electrons, the ions resulting with the charges and the fi

nal chemical formula of the compund.
Ba and O,
Al and O,
Mg and P,
Na and O,
Ca and Cl​
Chemistry
1 answer:
fgiga [73]3 years ago
6 0

Answer:

BaO

  • Ba gives up two electrons and becomes Ba⁺²
  • O takes two electron and becomes O⁻²

Al₂O₃

Mg₃P₂

Na₂O

CaCl₂

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Sometimes clothes removed from the dryer cling together. What kinds of charges are on the clothes ?
inn [45]

The answer is "opposite charges."

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3 years ago
Someone help me , quick​
sashaice [31]

When you ride a bicycle, several things happen that require energy and it's transformation. You pedaling the bike is transforming chemical energy, supplied by the breakdown of the food you eat, into mechanical energy to turn the pedals. The chemical energy is potential and the mechanical energy is kinetic.

4 0
3 years ago
iron is made by a reduction of iron oxide with carbon monoxide. Fe2O3+3CO-2Fe+3CO2. Calculate the mass of iron that can be forme
lyudmila [28]

Answer:

Mass = 88.12 g

Explanation:

Given data:

Mass of iron oxide = 126 g

Mass of iron formed = ?

Solution:

Chemical equation:

Fe₂O₃ + 3CO    →      2Fe + 3CO₂

Number of moles of iron oxide:

Number of moles = mass/molar mass

Number of moles = 126 g/ 159.69 g/mol

Number of moles = 0.789 mol

Now we will compare the moles of iron with iron oxide.

                      Fe₂O₃           :             Fe

                         1                 :               2

                   0.789              :            2/1×0.789 = 1.578 mol

Mass of iron:

Mass = number of moles ×molar mass

Mass = 1.578 mol × 55.84 g/mol

Mass = 88.12 g

4 0
3 years ago
Design a synthesis of 2-bromo-1-chloro-4-nitrobenzene from benzene or any mono-substituted benzene. Part 1 out of 6 choose the b
Oxana [17]

2-bromo-1-chloro-4-nitrobenzene  is being synthesized in following sequence:

Step 1: Chlorination of Benzene:

                                                     This is Halogenation reaction of benzene. In this step benzene is reacted with Chlorine gas in the presence of lewis acid (i.e. FeCl₃). This results in the formation of Chlorobenzene as shown in red step below.

Step 2: Nitration of Chlorobenzene:

                                                          The chlorine atom on benzene has a ortho para directing effect. Therefore, the nitration of chlorobenzene will yield para nitro chlorobenzene as shown in blue step below.

Step 3: Bromination of 1-chloro-4-nitrobenzene:

                                                                               In this step bromination is done by reacting bromine in the presence of lewis acid. The chlorine being ortho para directing in nature and nitro group being meta directing in nature will direct the incoming Br⁺ (electrophile) to the desired location. Hence, 2-bromo-1-chloro-4-nitrobenzene is synthesized in good yield.

6 0
3 years ago
A sample of H2 gas (12.28 g) occupies 100.0 L at 400.0 K and 2.00 atm. A sample weighing 9.49 g occupies ________ L at 353 K and
lutik1710 [3]

Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, you know:

  • P= 2 atm
  • V= ?
  • n= 9.49 gramsx\frac{1 mole}{2 grams} = 4.745moles being 2g/mole  the molar mass of H2, that is, the amount of mass that a substance contains in one mole.
  • R= 0.082 \frac{atmL}{molK}
  • T= 353 K

Replacing:

2 atm× V = 4.745 moles× 0.082\frac{atmL}{molK}× 353 K

Solving:

V = (4.745 moles× 0.082\frac{atmL}{molK}× 353 K)÷ 2 atm

<u><em>V= 68.67 L</em></u>

Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Learn more:

  • brainly.com/question/4147359?referrer=searchResults
5 0
3 years ago
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