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ira [324]
4 years ago
11

How do you write in words 4.110 and 4.10?

Mathematics
2 answers:
ohaa [14]4 years ago
8 0

The <em>correct answers</em> are:

"Four and 11 hundredths" or "four and one hundred ten thousandths"; and

"Four and ten hundredths" or "four and one tenth."

Explanation:

In the first decimal, the digit 4 is in front of the decimal. This is read "Four and". After the decimal, we have 110. We look at the last place, digit, 0. Going by our place value, this is in the thousandths place. We read the block of digits 110 as "one hundred ten" and it is "thousandths." This makes the number "four and one hundred ten thousandths."

Alternatively, if we drop the zero, we would have 4.11. It is still "four and"; this time the last digit is 1, and it is in the hundredths place. 11 is read as "eleven", so this would be "four and eleven hundredths."

For the second number, 4.10, we have a 4 in front of the decimal, so we again have "four and". Our last digit is 0, and it is in the hundredths place; 10 is read "ten", so we have "four and ten hundredths."

Alternatively, if we drop the zero, we have 4.1. This is still "four and"; the 1 is now our last digit, and it is in the tenths place, so we have "four and one tenth."

Lana71 [14]4 years ago
8 0

For this case we have the following numbers:

4.110

4.10

We observed that:

4.110> 4.10

Therefore, we should not confuse both numbers.

The correct way to write both numbers is given by:

4.110 = four point one hundred ten thousandths

4.10 = four point ten hundredths

Answer:

4.110 = four point one hundred ten thousandths

4.10 = four point ten hundredths

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If discount rate is 12%, the present value of Rs X recieved at the end of each year for the next five years is equal to
myrzilka [38]

Answer:

Present Value = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

Step-by-step explanation:

To find - If discount rate is 12%, the present value of Rs X received at the end of each year for the next five years is equal to .... ?

Solution -

We know that, formula for finding the Present vale is given by

Present value = Future value / (1 + r)ⁿ

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Now,

Here in the question, we have

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n = 5

Also, Given that, we have received Rs X at the end of each year

So,

Present Value = \frac{X}{(1 + 0.12)^{1} }  + \frac{X}{(1 + 0.12)^{2} }  + \frac{X}{(1 + 0.12)^{3} }  + \frac{X}{(1 + 0.12)^{4} }  + \frac{X}{(1 + 0.12)^{5} }

                        = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

⇒Present Value = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

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Round to the neares cent:

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