<h3><u>
Answer:</u></h3>
When a welder must certify for their appropriate welder's certifications, all of the samples are basically flat work. Simple tack welds to deep fill welds are required.
<h3><u>
Explanation:</u></h3>
If you are welding two pieces of metal together, having the work as flat as possible allows for the best access for the weld to be proper. There are often more times then not that the work will not be in a flat position so if you are really just starting out, your practice welds should be made on flat work to get the skill necessary to weld well in other positions.
Answer:
15.65 MPa 150 times of human body internal pressure
Explanation:
Given:
- Depth of the ocean for offshore drilling d = 1 mile
Find:
Determine the pressure at that location
What would happen to an unprotected, exposed person at that depth?
Solution:
- The pressure at a certain depth of a fluid can be calculated with:
P = p_w*g*d
Where, P is the pressure , p_w is the density of water ( 997 kg / m^3 ).
- Hence @ d = 1.0 mile = 1.6 km = 1600 m:
P = 997*9.81*1600
P = 15.65 MPa
- Whereas the pressure inside a human body is 101 KPa, Pressure under ocean @ 1 mile of depth is 150 times in magnitude, enough to crush the human body!
Answer: 5) KC-0.78 KU
Explanation:
KC-0.78 KU is not defined for tuning of overshoot on the Start-up as, this method is only applicable for there is some turning constants and also there is no overshoot during the normally modulating control. But some overshoot at start up are applicable. For the continuous cycling method, some overshoot is same as for closed loop tuning.
Answer:
Look at some engineering colleges and set up or join a public zoom meeting. For example, some colleges have sign ups for zoom calls on set dates and you‘re able to ask questions.
Explanation:
Answer:
Δr=20.45 %
Explanation:
Given that
Rake angle α = 15°
coefficient of friction ,μ = 0.15
The friction angle β
tanβ = μ
tanβ = 0.15
β=8.83°
2φ + β - α = 90°
φ=Shear angle
2φ + 8.833° - 15° = 90°
φ = 48.08°
Chip thickness r given as
r=0.88
New coefficient of friction ,μ' = 0.3
tanβ' = μ'
tanβ' = 0.3
β'=16.69°
2φ' + β' - α = 90°
φ'=Shear angle
2φ' + 16.69° - 25° = 90°
φ' = 49.15°
Chip thickness r' given as
r'=0.70
Percentage change
Δr=20.45 %
