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wariber [46]
3 years ago
8

(8 points) Consider casting a concrete driveway 40 feet long, 12 feet wide and 6 in. thick. The proportions of the mix by weight

are given as 1:2:3 for cement, sand, and gravel with w/c of 0.50. The specific gravities of sand and gravel are 2.60 and 2.70 respectively. Entrained air content is 7.5%. How many pounds of cement, water, sand, and gravel are needed for the driveway?
Engineering
1 answer:
FromTheMoon [43]3 years ago
8 0

Answer:

Weight of cement = 10909.08 pounds

Weight of sand = 18008.64 lb

Weight of gravel = 28051.92 lb

Weight of water = 5454.54 lb

Explanation:

given data

length = 40 feet

width = 12 feet

thickness = 6 in = 0.5 feet

mix proportion = 1:2:3

specific gravity of cement = 3.15

specific gravity of sand = 2.60

specific gravity of gravel = 2.70

water to cement ratio = 0.50

solution

first we get here total volume that is

volume = length × width × thickness    ...........1

volume = 40  × 12 × 0.5

volume = 240 feet³

and

now we get here dry volume of concrete that will be

Dry volume =  wet volume ×  1.54    .......................2

Dry volume = 240 × 1.54

Dry volume =  360 feet³

and

we have given air content entrained is = 7.5 %

so required volume will be as

required volume = Dry volume × ( 1 - 7% )    .............3

required volume = 360 × ( 1 - 7.5 % )

required volume = 333 feet³  

and

total ratio is

total ratio = 1+ 2+ 3

total ratio = 6

so volume of sand cement and gravel will be

volume of  cement = \frac{1}{6} \times 333  

volume of  cement = 55.5 feet³

volume of  sand  = \frac{2}{6} \times 333

volume of  sand  = 111 feet³

volume of  gravel = \frac{3}{6} \times 333  

volume of  gravel = 166.5 feet³

and

now we get here weight of sand cement and gravel as

weight = volume ×  specific gravity × density of water   .............4

and now put here value and we get

Weight of cement = 55.5 × 3.15 × 62.4

Weight of cement = 10909.08 pounds

and

Weight of sand = 111 × 2.60 × 62.4

Weight of sand = 18008.64 lb

and

Weight of gravel = 166.5 × 2.7 × 62.4

Weight of gravel = 28051.92 lb

and

Weight of water = 0.5 of weight of cement

Weight of water  = 0.5 ×  1090.9.08

Weight of water = 5454.54 lb

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Answer:

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Explanation:

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ans since volume of solution is 1 L thus concentration of NaCl is ,C= number of moles/Volume of solution in Litres

C= 0.5989mol/ 1L

=0.5989 M

Since 1 mol NaCL disssociates to form 2 moles of ions of Na+ andCl- Thus van't hoff factor i=2

And osmotic pressure  = iCRT ------------------------------(1)( Where R= 0.0821 L.atm/mol.K and T= 25oC= 298.15 K)

Putting in equation 1 ,we get  = 2*(0.5989 mol/L)*(0.0821 L.atm/mol.K)*298.15 K

=29.319 atm

Now as the water gets filtered out of the membrane,the water's volume decreases and concentration C of NacL increases, thus osmotic pressure also increases.Thus, at 50% water been already filtered out, the osmotic pressure at the membrane will be maximum

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Answer:

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Explanation:

#include <iostream>

using namespace std;

void insert(int* arr, int* size, int value, int position){

if(position<0 || position>=*size){

cout<<"position is greater than size of the array"<<endl;

return ;

}

*size = *size + 1 ;

for(int i=*size;i>position;i--){

arr[i] = arr[i-1];

}

arr[position] = value ;

}

void print(int arr[], int size){

for(int i=0;i<size;i++){

cout<< arr[i] <<" ";

}

cout<<" "<<endl;

}

void remove(int* arr, int* size, int position){

* size = * size - 1 ;

for(int i=position;i<*size;i++){

arr[i] = arr[i+1];

}

}

int count(int arr[], int size, int target){

int total = 0 ;

for(int i=0;i<size;i++){

if(arr[i] == target)

total += 1 ;

}

return total ;

}

int main()

{

int size;

cout<<"Enter the initial size of the array:";

cin>>size;

int arr[size],val;

cout<<"Enter the values to fill the array:"<<endl;

for(int i=0;i<size;i++){

cin>>val;

arr[i] = val ;

}

int choice = 5,value,position,target ;

do{

cout<<"Make a selection:"<<endl;

cout<<"1) Insert"<<endl;

cout<<"2) Remove"<<endl;

cout<<"3) Count"<<endl;

cout<<"4) Print"<<endl;

cout<<"5) Exit"<<endl;

cout<<"Choice:";

cin>>choice;

switch(choice){

case 1:

cout << "Enter the value:";

cin>>value;

cout << "Enter the position:";

cin>>position;

insert(arr,&size,value,position);

break;

case 2:

cout << "Enter the position:";

cin>>position;

remove(arr,&size,position);

break;

case 3:

cout<<"Enter the target value:";

cin>>target;

cout <<"The number of times "<<target<<" occured in your array is:" <<count(arr,size,target)<<endl;

break;

case 4:

print(arr,size);

break;

case 5:

cout <<"Thank you..."<<endl;

break;

default:

cout << "Invalid choice..."<<endl;

}

}while(choice!=5);

return 0;

}

Kindly check the attached images below for the code output.

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3 years ago
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