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3 years ago

Which one of the following statements about the Wright brothers is not true?

Engineering

1 answer:

11111nata11111 [884]3 years ago

3 0

On December 17, 1903, the Flyer flew for two minutes and 1200 feet.

Answer: Option B.

Explanation:

The first successful flight that was taken by the "Wright brothers" on seventeenth of December in the year 1903 was not for two minutes and more over there were four different flights that the brothers took on that same day.

The first one was for 12 seconds for 540 feet, the second flight was for thirteen seconds ans went up to 200 feet and the third flight was for fifteen seconds again for 200 feet. The fourth was the longest flight which lasted for 59 seconds.

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The hot-wire anemometer.' A hot-wire anemome ter is essentially a fine wire, usually made of platinum,which is heated electrical

Delicious77 [7]

Answer:

attached below

Explanation:

To derive the equation we have to make some assumptions

assumptions:

Assume T depends on Z alone

Assume uniform thermal and electrical conductivities (k and ke) in the wire, Assume a uniform heat

transfer coefficient h from the wire to the air stream.

attached below is the required derivation of the equation

7 0

3 years ago

2.31 LAB: Simple statistics Part 1 Given 4 integers, output their product and their average, using integer arithmetic. Ex: If th

Elden [556K]

Answer:

Explanation:

Note: Integer division discards the fraction. Hence the average of 8, 10, 5, 4 is output as 6, not 6.75.

Note: The test cases include four very large input values whose product results in overflow. You do not need to do anything special, but just observe that the output does not represent the correct product (in fact, four positive numbers yield a negative output; wow).

Submit the above for grading. Your program will fail the last test cases (which is expected), until you complete part 2 below.

Part 2: Also output the product and average, using floating-point arithmetic.

Output each floating-point value with three digits after the decimal point, which can be achieved as follows: System.out.printf("%.3f", yourValue);

Ex: If the input is 8, 10, 5, 4, the output is:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

double average_arith = (num1+num2+num3+num4)/4.0;

double product_arith = num1*num2*num3*num4;

int result1 = (int) average_arith;

int result2 = (int) product_arith;

System.out.printf("%d %d\n",result2,result1);

System.out.printf("%.3f %.3f\n",product_arith,average_arith);

}

expected output : 1600.000 6.750

5 0

3 years ago

Read 2 more answers

A company specification calls for a steel component to have a minimum tensile strength of 1240 MPa. Tension tests are conducted

Pavlova-9 [17]

Answer:

a) The minimum acceptable value is 387.5 HV using Vickers hardness test.

b) The minimum acceptable value is 39.4 HRC using Rockwell C hardness test.

Explanation:

To get the tensile strength of a material from its hardness, we multiply it by an empirical constant that depends on things like yield strength, work-hardening, Poisson's ratio and geometrical factors. The incidence of cold-work varies this relationship.

According to DIN 50150 (a conversion table for hardness), the constant for Vickers hardness is ≈ 3.2 (an empirical approximate):

$\mbox{Tensile strength}=HV*3.2\\\\HV = \frac{\mbox{Tensile strength}}{3.2} =\frac{1240}{3.2}=387.5$

According to DIN 50150, the constant for Rockwell C hardness test is ≈31.5 around this values of tensile strength:

$\mbox{Tensile strength}=HRC*31.5\\\\HRC = \frac{\mbox{Tensile strength}}{31.5} =\frac{1240}{31.5}=39.4$

8 0

3 years ago

Water (cp = 4180 J/kg·°C) enters the 2.5 cm internal diameter tube of a double-pipe counter-flow heat exchanger at 17°C at a rat

aksik [14]

Answer:

Length = 129.55m, 129.55m

Explanation:

Given:

cp of water = 4180 J/kg·°C

Diameter, D = 2.5 cm

Temperature of water in = 17°C

Temperature of water out = 80°C

mass rate of water =1.8 kg/s.

Steam condensing at 120°C

Temperature at saturation = 120°C

hfg of steam at 120°C = 2203 kJ/kg

overall heat transfer coefficient of the heat exchanger = 700 W/m2 ·°C

U = 700 W/m2 ·°C

Since Temperature of steam is at saturation,

temperature of steam going in = temperature of steam out = 120°C

Energy balance:

Heat gained by water = Heat loss by steam

Let specific capacity of steam = 2010kJ/Kg .°C

Find attached the full solution to the question.

3 0

3 years ago

Engine horsepower decreases ________% for every___________feet above sea level.

Nitella [24]

Answer:

Engine horsepower decreases 3.5% for every 1,000 feet above sea level.

4 0

3 years ago