Answer : The final velocity of the ball is, 12.03 m/s
Explanation :
By the 3rd equation of motion,
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
where,
s = distance covered by the object = 6.93 m
u = initial velocity = 2.99 m/s
v = final velocity = ?
a = acceleration = ![9.8m/s^2](https://tex.z-dn.net/?f=9.8m%2Fs%5E2)
Now put all the given values in the above equation, we get the final velocity of the ball.
![v^2-(2.99m/s)^2=2\times (9.8m/s^2)\times (6.93m)](https://tex.z-dn.net/?f=v%5E2-%282.99m%2Fs%29%5E2%3D2%5Ctimes%20%289.8m%2Fs%5E2%29%5Ctimes%20%286.93m%29)
![v=12.03m/s](https://tex.z-dn.net/?f=v%3D12.03m%2Fs)
Thus, the final velocity of the ball is, 12.03 m/s
Answer:
Explanation:
From the given question:
Using the distortion energy theory to determine the factors of safety FOS can be expressed by the relation:
![\dfrac{Syt}{FOS}= \sqrt{ \sigma x^2+\sigma y^2-\sigma x \sigma y+3 \tau_{xy^2}}](https://tex.z-dn.net/?f=%5Cdfrac%7BSyt%7D%7BFOS%7D%3D%20%5Csqrt%7B%20%5Csigma%20x%5E2%2B%5Csigma%20%20y%5E2-%5Csigma%20x%20%5Csigma%20y%2B3%20%5Ctau_%7Bxy%5E2%7D%7D)
where; syt = strength in tension and compression = 350 MPa
The maximum shear stress theory can be expressed as:
![\tau_{max} = \dfrac{Syt}{2FOS}](https://tex.z-dn.net/?f=%5Ctau_%7Bmax%7D%20%3D%20%5Cdfrac%7BSyt%7D%7B2FOS%7D)
where;
![\tau_{max} =\sqrt{ (\dfrac{\sigma x-\sigma y}{2})^2+ \tau _{xy^2](https://tex.z-dn.net/?f=%5Ctau_%7Bmax%7D%20%3D%5Csqrt%7B%20%28%5Cdfrac%7B%5Csigma%20x-%5Csigma%20%20y%7D%7B2%7D%29%5E2%2B%20%5Ctau%20_%7Bxy%5E2)
a. Using distortion - energy theory formula:
![\dfrac{350}{FOS}= \sqrt{94^2+0^2-94*0+3 (-75)^2}}](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B94%5E2%2B0%5E2-94%2A0%2B3%20%28-75%29%5E2%7D%7D)
![\dfrac{350}{FOS}=160.35](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D160.35)
![{FOS}=\dfrac{350}{160.35}](https://tex.z-dn.net/?f=%7BFOS%7D%3D%5Cdfrac%7B350%7D%7B160.35%7D)
FOS = 2.183
USing the maximum-shear stress theory;
![\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{94-0}{2})^2+ (-75)^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%20%28%5Cdfrac%7B94-0%7D%7B2%7D%29%5E2%2B%20%28-75%29%5E2)
![\dfrac{350}{2 FOS} =88.51](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D88.51)
![\dfrac{350}{ FOS} =2 \times 88.51](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B%20FOS%7D%20%20%3D2%20%5Ctimes%2088.51)
![{ FOS} =\dfrac{350}{2 \times 88.51}](https://tex.z-dn.net/?f=%7B%20FOS%7D%20%20%3D%5Cdfrac%7B350%7D%7B2%20%5Ctimes%2088.51%7D)
FOS = 1.977
b. σx = 110 MPa, σy = 100 MPa
Using distortion - energy theory formula:
![\dfrac{350}{FOS}= \sqrt{ 110^2+100^2-110*100+3(0)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B%20110%5E2%2B100%5E2-110%2A100%2B3%280%29%5E2%7D)
![\dfrac{350}{FOS}= \sqrt{ 12100+10000-11000](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B%2012100%2B10000-11000)
![\dfrac{350}{FOS}=105.3565](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D105.3565)
![FOS=\dfrac{350}{105.3565}](https://tex.z-dn.net/?f=FOS%3D%5Cdfrac%7B350%7D%7B105.3565%7D)
FOS =3.322
USing the maximum-shear stress theory;
![\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{110-100}{2})^2+ (0)^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%20%28%5Cdfrac%7B110-100%7D%7B2%7D%29%5E2%2B%20%280%29%5E2)
![\dfrac{350}{2 FOS} ={ (\dfrac{110-100}{2})^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%7B%20%28%5Cdfrac%7B110-100%7D%7B2%7D%29%5E2)
![\dfrac{350}{2 FOS} =25](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D25)
FOS = 350/2×25
FOS = 350/50
FOS = 70
c. σx = 90 MPa, σy = 20 MPa, τxy =−20 MPa
Using distortion- energy theory formula:
![\dfrac{350}{FOS}= \sqrt{ 90^2+20^2-90*20+3(-20)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B%2090%5E2%2B20%5E2-90%2A20%2B3%28-20%29%5E2%7D)
![\dfrac{350}{FOS}= \sqrt{ 8100+400-1800+1200}](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%20%5Csqrt%7B%208100%2B400-1800%2B1200%7D)
![\dfrac{350}{FOS}= 88.88](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7BFOS%7D%3D%2088.88)
FOS = 350/88.88
FOS = 3.939
USing the maximum-shear stress theory;
![\dfrac{350}{2 FOS} =\sqrt{ (\dfrac{90-20}{2})^2+ (-20)^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%20%28%5Cdfrac%7B90-20%7D%7B2%7D%29%5E2%2B%20%28-20%29%5E2)
![\dfrac{350}{2 FOS} =\sqrt{ (35)^2+ (-20)^2](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%20%2835%29%5E2%2B%20%28-20%29%5E2)
![\dfrac{350}{2 FOS} =\sqrt{ 1225+ 400](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D%5Csqrt%7B%201225%2B%20400)
![\dfrac{350}{2 FOS} =40.31](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7B2%20FOS%7D%20%20%3D40.31)
![FOS} =\dfrac{350}{2*40.31}](https://tex.z-dn.net/?f=FOS%7D%20%20%3D%5Cdfrac%7B350%7D%7B2%2A40.31%7D)
FOS = 4.341
Answer:
a. 318.2k
b. 45.2kj
Explanation:
Heat transfer rate to an object is equal to the thermal conductivity of the material the object is made from, multiplied by the surface area in contact, multiplied by the difference in temperature between the two objects, divided by the thickness of the material.
See attachment for detailed analysis
Answer:
Option (c) and option (d)
Explanation:
Eutectic system is one in which a solid and homogeneous mixture of two or more substances resulting in the formation of super lattice is formed which can melt or solidify at a temperature lower than the melting point of any individual metal.
Eutectic alloys are those which have its components mixed in a specific ratio.
It is the composition in an alloy system for which both the liquidus and solidus temperatures are equal.
Eutectic alloys have the composition in which the melting point of the metal is lower than the other alloy composition.
Answer and Explanation:
• 1 thread awaits the incoming request
• 1 thread responds to the request
• 1 thread reads the hard disk
A multithreaded file server is better than a single-threaded server and a finite-state machine server because it provides better response compared to the rest and can make use of the shared Web data.
Yes, there are circumstances in which a single-threaded server might be better. If it is designed such that:
- the server is completely CPU bound, such that multiple threads isn't needed. But it would account for some complexity that aren't needed.
An example is, the assistance number of a telephone directory (e.g 7771414) for an community of say, one million people. Consider that each name and telephone number record is sixty-four characters, the whole database takes 64 MB, and can be easily stored in the server's memory in order to provide quick lookup.
NOTE:
Multiple threads lead to operation slow down and no support for Kernel threads.