Answer:
E= 15 GPa.
Explanation:
Given that
Length ,L = 0.5 m
Tensile stress ,σ = 10.2 MPa
Elongation ,ΔL = 0.34 mm
lets take young modulus = E
We know that strain ε given as



We know that

Therefore the young's modulus will be 15 GPa.
Answer:
hello your question has a missing part below is the missing part
Consider the string length equal to 
answer : 2cos(2t) sin(2x) - 10cos(10t)sin(10x)
Explanation:
Given string length =
distorted function f(x) = 2sin(2x) - 10sin(10x)
Determine the wave formed in the string
attached below is a detailed solution of the problem
Answer:
F=531831381
Explanation:
There are two ways of doing this question:
1) By Formula
2) By Using Compound interest Table
By Formula:

Where:
F is future value
A is annual amount per year
i is interest rate
n is number of years

F=531831381
By Using Compound interest Table:
F=A(F/A,i,n)
From Table F/A at i=8% and n=8 is 10.6366
F=50000000*(10.6366)
F=531830000≅531831381
The difference in two answers is due to decimal points if you take value from table to greater decimal points you will get the exact answer as by using formula.
Answer is given below
Explanation:
we know that some common types of throttling devices are
- Hard -throttling devices
- Capillary valve
- Constant pressure throttling devices
- Thermostatic expansion valve
- Float expansion valve
so here throttling devices commonly used in refrigeration and air-conditioning because
- To reduce the coolant pressure, the high pressure of the refrigerant from the condenser is necessary to reduce the evaporation to obtain evaporation at the right temperature
- To meet the refrigerated load, the throttling valve flows through the coolant to cool the load at high temperatures.
Answer:
the width of the turning roadway = 15 ft
Explanation:
Given that:
A ramp from an expressway with a design speed(u) = 30 mi/h connects with a local road
Using 0.08 for superelevation(e)
The minimum radius of the curve on the road can be determined by using the expression:

where;
R= radius
= coefficient of friction
From the tables of coefficient of friction for a design speed at 30 mi/h ;
= 0.20
So;



R = 214.29 ft
R ≅ 215 ft
However; given that :
The turning roadway has stabilized shoulders on both sides and will provide for a onelane, one-way operation with no provision for passing a stalled vehicle.
From the tables of "Design widths of pavement for turning roads"
For a One-way operation with no provision for passing a stalled vehicle; this criteria falls under Case 1 operation
Similarly; we are told that the design vehicle is a single-unit truck; so therefore , it falls under traffic condition B.
As such in Case 1 operation that falls under traffic condition B in accordance with the Design widths of pavement for turning roads;
If the radius = 215 ft; the value for the width of the turning roadway for this conditions = 15ft
Hence; the width of the turning roadway = 15 ft