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yan [13]
4 years ago
10

Derive an algebraic equation for the vertical force that the bench exerts on the book at the lowest point of the circular path i

n terms of the book’s mass mb, tangential speed vb, radius R of the path, and physical constants, as appropriate. Do not substitute any numerical values for variables or physical constants.

Physics
1 answer:
fiasKO [112]4 years ago
4 0

Answer:

The algebraic equation is:

F_{v} =\frac{m_{b}v_{b}^{2}   }{R} -m_{b} g

Explanation:

Given information:

mb = book's mass

vb = tangential speed

R = radius of the path

Question: Derive an algebraic equation for the vertical force, Fv = ?

To derive the equation, we need to draw a force diagram for this case, please, see the attached diagram. As you can see, there are three types of forces acting on the system. Two up and one of the weight acting down. Therefore, the algebraic equation is as follows:

F_{v} =\frac{m_{b}v_{b}^{2}   }{R} -m_{b} g

The variables were defined above and g is the gravity.

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What is the instantaneous acceleration of the particle at point B?
Vikentia [17]
Acceleration is a measure of how fast the velocity of a particle/object is changing at a point. Therefore, acceleration can be measured by finding the slope of the velocity of the particle at a certain point.

Since we are given the graph of velocity, we have to find the slope of the particle at point B. In the given graph, the slope of the velocity of the particle at point B is zero. Therefore, the acceleration of the particle at point B is 0.

Hope this helps!
7 0
3 years ago
A horizontal spring is lying on a frictionless surface. One end of the spring is attaches to a wall while the other end is conne
JulsSmile [24]

Answer:

v_f = 1.05 m/s

Explanation:

From conservation of energy;

E_f = E_i

Thus,

(1/2)m(v_f)² + (1/2)I(ω_f)² + m•g•h_f + (1/2)k•(x_f)² = (1/2)m(v_i)² + (1/2)I(ω_i)² + m•g•h_i + (1/2)k•(x_i)²

This reduces to;

(1/2)m(v_f)² + (1/2)Ik(x_f)² = (1/2)k•(x_i)²

Making v_f the subject, we have;

v_f = [√(k/m)] * [√((x_i)² - (x_f)²)]

We know that ω = √(k/m)

Thus,

v_f = ω[√((x_i)² - (x_f)²)]

Plugging in the relevant values to obtain;

v_f = 17.8[√((0.068)² - (0.034)²)]

v_f = 17.8[0.059] = 1.05 m/s

3 0
3 years ago
Estimate the change in gravitational potential energy when a person with mass 80 kg rise from bed to a standing position. Assumi
Doss [256]

Answer:

change in gravitational potential energy Δ PE = 392 J

Explanation:

given data

mass of the person m  = 80 kg

height of the centre of mass Δh = 0.50 m

to find out

change in gravitational potential energy

solution

we get here change in gravitational potential energy that is express here as

change in gravitational potential energy Δ PE = m × g × Δh     .........1

put here value we get

change in gravitational potential energy Δ PE = m × g × Δh

change in gravitational potential energy Δ PE = 80 × 9.8 × 0.50

change in gravitational potential energy Δ PE = 392 J

7 0
3 years ago
A 5000 g toy car starts from rest and moves a distance of 300 cm in 3 s under the action of a single constant force. Determine t
sveticcg [70]

Answer:

3.33 N

Explanation:

First, find the acceleration.

Given:

Δx = 3 m

v₀ = 0 m/s

t = 3 s

Find: a

Δx = v₀ t + ½ at²

3 m = (0 m/s) (3 s) + ½ a (3 s)²

a = ⅔ m/s²

Use Newton's second law to find the force.

F = ma

F = (5 kg) (⅔ m/s²)

F ≈ 3.33 N

4 0
3 years ago
Can someone help me with one through seven I will mark you the brainly
ki77a [65]

Answer:

1.  F = M x A

2. Force  

3. 2nd Law: Force

4. a, b, c (in order)

5. 3rd Law: Action and Reaction

6. b, c, a (in order)

7. 1st Law: Inertia

3 0
3 years ago
Read 2 more answers
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