Anything carbon in composition
The composite material is composed of carbon fiber and epoxy resins. Now, density is an intensive unit. So, to approach this problem, let's assume there is 1 gram of composite material. Thus, mass carbon + mass epoxy = 1 g.
Volume of composite material = 1 g / 1.615 g/cm³ = 0.619 cm³
Volume of carbon fibers = x g / 1.74 g/cm³
Volume of epoxy resin = (1 - x) g / 1.21 g/cm³
a.) V of composite = V of carbon fibers + V of epoxy resin
0.619 = x/1.74 + (1-x)/1.21
Solve for x,
x = 0.824 g carbon fibers
1-x = 0.176 g epoxy resins
Vol % of carbon fibers = [(0.824/1.74) ÷ 0.619]*100 =<em> 76.5%</em>
b.) Weight % of epoxy = 0.176 g epoxy/1 g composite * 100 = <em>17.6%</em>
Weight % of carbon fibers = 0.824 g carbon/1 g composite * 100 = <em>82.4%</em>
Given :
Mass of Ba(OH)₂ , m = 35.5 g.
Volume of mixture, V = 325 mL = 0.325 L.
To Find :
The molarity of a solution.
Solution :
We know, molarity of a solution is given by :
We know, molecular mass of Ba(OH)₂ is given by :
M.M. = 171 g/mol
Putting all these values in given equation, we get :
Hence, this is the required solution.
Answer:
oxygen
Explanation:any reaction with burning involves mixing oxygen
this is correct
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