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Ainat [17]
3 years ago
11

A football player kicks a football, from ground level, with an initial velocity of 27.0 m/s at an angle 30° above the horizontal

.
a. What is the maximum height the ball attained?
b. How long did it take the ball to return to the launching height?
C. How far away did it land?​
Physics
1 answer:
Bond [772]3 years ago
6 0

Answer:

See answers below

Explanation:

a.

(vf)² = (vi)² + 2gy

0 = (27sin30°)² + 2(-9.8)y

y = 36.3 m

b.

vf = vi + gt

0 = (27sin30°) + (-9.8)t

t = 2.72 s

2.72 x 2 = 5.44 s

c.

x = (vi)t + (1/2)at²

x = (27cos30°)(5.44) + 0

x = 22.66 m

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Answer:

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Explanation:

We are given that

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Let one charge=q_1=q\mu C=q\times 10^{-6}C

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36\times 10^{-3}=9\times 10^{9}\times \frac{q\times 10^{-6}\times(10-q)\times 10^{-6}}{(2\times 10^{-2})^2}

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0.0016=10q-q^2

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Using the formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

q=9.999 and q=0.00016

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q_2=10-0.00016=9.99984

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q_1=9.9998\mu C and q_2=0.0002\mu C

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