Answer:
In a house there is a lot less space so there is no where for the sound to travel, but if you are outside there is a lot more space so therefore, the sound can travel anywhere.
Explanation:
Answer:
The amount of mass that needs to be converted to release that amount of energy is ![1.122 X 10^{-7} kg](https://tex.z-dn.net/?f=1.122%20X%2010%5E%7B-7%7D%20%20kg)
Explanation:
From Albert Einstein's Energy equation, we can understand that mass can get converted to energy, using the formula
![E= \Delta mc^{2}](https://tex.z-dn.net/?f=E%3D%20%5CDelta%20mc%5E%7B2%7D)
where
= change in mass
c = speed of light = ![3 \times 10 ^{8}m/s](https://tex.z-dn.net/?f=3%20%5Ctimes%2010%20%5E%7B8%7Dm%2Fs)
Making m the subject of the formula, we can find the change in mass to be
![\Delta m = \frac{E}{c^{2}}= \frac{1.01 \times 10^{3} \times 10^{7}}{(3 \times 10^{8})^{2}}= 1.122 \times 10 ^{-7}kg](https://tex.z-dn.net/?f=%5CDelta%20m%20%3D%20%5Cfrac%7BE%7D%7Bc%5E%7B2%7D%7D%3D%20%5Cfrac%7B1.01%20%5Ctimes%2010%5E%7B3%7D%20%5Ctimes%2010%5E%7B7%7D%7D%7B%283%20%5Ctimes%2010%5E%7B8%7D%29%5E%7B2%7D%7D%3D%201.122%20%5Ctimes%2010%20%5E%7B-7%7Dkg)
There fore, the amount of mass that needs to be converted to release that amount of energy is 1.122 X 10 ^-7 kg
Answer:
lipids are insoluble in water which is why lipids are often found in biological membranes and other waterproof coverings.
Answer:
The sphere C carries no net charge.
Explanation:
- When brougth close to the charged sphere A, as charges can move freely in a conductor, a charge equal and opposite to the one on the sphere A, appears on the sphere B surface facing to the sphere A.
- As sphere B must remain neutral (due to the principle of conservation of charge) an equal charge, but of opposite sign, goes to the surface also, on the opposite part of the sphere.
- If sphere A is removed, a charge movement happens in the sphere B, in such a way, that no net charge remains on the surface.
- If in such state, if the sphere B (assumed again uncharged completely, without any local charges on the surface), is touched by an initially uncharged sphere C, due to the conservation of charge principle, no net charge can be built on sphere C.
The solution for this problem is:
Work it backwards: spring U = ½kx² = ½ * 4000N/m * (0.10m) ²
= 20 J
so the pre-impact of KE = 20 J = ½ * m * v² = ½ * 0.40kg * v²
v = 10 m/s → for the bullet/block.
Now conserve the momentum:
50g * u = 400g * 10m/s
u = 80 m/s is the arrow
velocity