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Dovator [93]
3 years ago
7

A 2 L balloon filled with gas is warmed from 280 K to 700 K. What is the volume of the gas after it is heated?

Physics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

New volume, v2 = 0.8L

Explanation:

<u>Given the following data;</u>

Original Volume = 2L

Original Temperature = 280K

New Temperature = 700K

To find new volume V2, we would use Charles' law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

VT = K

\frac{V1}{T1} = \frac{V2}{T2}

\frac{V1}{T1} = \frac{V2}{T2}

Making V2 as the subject formula, we have;

V_{2}= \frac{V1}{T1} * T_{2}

V_{2}= \frac{2}{700} * 280

V_{2}= 0.0029 * 280

V2 = 0.8L

Therefore, the volume of the gas after it is heated is 0.8L.

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Answer:C, Atoms of iron are different from atoms of nickel.

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6 0
3 years ago
How big is the image produced by the periscope compared to the size of the object
ipn [44]

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<span>Put a lens in the middle of the tube </span>

<span>? </span>

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<span>Normally they are set across from a concealed entrance or one that is hard to see both ways like the inside of a hairpin bend. Sometimes only to help in one direction. </span>

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8 0
3 years ago
An object executing simple harmonic motion has a maximum speed of 4.3 m/s and a maximum acceleration of 0.65 m/s2 . find (a) the
Alexxx [7]
(1) The position around equilibrium of an object in simple harmonic motion is described by
x(t) = A \cos (\omega t)
where
A is the amplitude of the motion
\omega is the angular frequency.

The velocity is the derivative of the position:
v(t)=-\omega A \sin(\omega t) = -v_0 \sin (\omega t)
where 
v_0 = \omega A is the maximum velocity of the object.

The acceleration is the derivative of the velocity:
a(t)=- \omega^2 A \cos (\omega t) = -a_0 \cos (\omega t)
where
a_0=\omega^2 A is the maximum acceleration of the object.

We know from the problem both maximum velocity and maximum acceleration:
v_0 = \omega A = 4.3 m/s
a_0 = \omega^2 A = 0.65 m/s^2
From the first equation, we get
A= \frac{4.3 }{\omega} (1)
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\omega=0.15 rad/s
while the amplitude is  (using (1)):
A=28.7 m


(b) We found in the previous step that the angular frequency of the motion is
\omega=0.15 rad/s
But the angular frequency is related to the period by
T= \frac{2 \pi}{\omega}
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T= \frac{2 \pi}{\omega}= \frac{2 \pi}{0.15 rad/s}=41.9 s
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3 years ago
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The secondary clarifiers are the ones responsible for the removal of

biological nutrients in the waste water through biofiltration etc.

Read more on brainly.com/question/25085634

6 0
2 years ago
Read 2 more answers
A prediction or educated guess that can be tested is ?
Ksivusya [100]
An educated guess is a “hypothesis”
7 0
3 years ago
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