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alex41 [277]
3 years ago
13

Compare and contrast infrasonic and ultrasonic vibrations

Physics
1 answer:
Olegator [25]3 years ago
8 0

Answer:

Explanation:

Ultrasonic waves are acoustic waves that are so high in frequency that humans can't hear them; however, infrasonic waves are sound waves that are lower in frequency than what humans can hear. A subsonic wave is a wave that is traveling slower than the speed of sound and a supersonic waves travels faster

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These waves are most harmful for living things.
scZoUnD [109]

Explanation:

G. gamma rays because they are produced by the hottest and most energetic objects in the universe, such as neutron stars and pulsars, supernova explosions, and regions around black holes.

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5 0
3 years ago
Draw a picture of an atom.include protons,neutrons, and electrons.
gogolik [260]
Hey, unfortunately it’s impossible for me to draw one for you here, but you should be able to draw it yourself pretty easily!

Answer:


An atom is built with a combination of three distinct particles: electrons, protons, and neutrons. Each atom has a center nucleus, where the protons and neutrons are densely packed together. Surrounding the nucleus are a group of orbiting electrons. And here is a picture that may assist your further :

Hope this helps
6 0
4 years ago
1 Beth isn't a very good student. She's very ......<br>A rude<br>B lazy<br>C clever​
kap26 [50]

Answer:

c she's very clever

Explanation:

5 0
3 years ago
Read 2 more answers
Which of these charges is experiencing the electric field with the largest magnitude? A 2C charge acted on by a 4 N electric for
Pavlova-9 [17]

Answer:

The highest electric field is experienced by a 2 C charge acted on by a 6 N electric force. Its magnitude is 3 N.

Explanation:

The formula for electric field is given as:

E = F/q

where,

E = Electric field

F = Electric Force

q = Charge Experiencing Force

Now, we apply this formula to all the cases given in question.

A) <u>A 2C charge acted on by a 4 N electric force</u>

F = 4 N

q = 2 C

Therefore,

E = 4 N/2 C = 2 N/C

B) <u>A 3 C charge acted on by a 5 N electric force</u>

F = 5 N

q = 3 C

Therefore,

E = 5 N/3 C = 1.67 N/C

C) <u>A 4 C charge acted on by a 6 N electric force</u>

F = 6 N

q = 4 C

Therefore,

E = 6 N/4 C = 1.5 N/C

D) <u>A 2 C charge acted on by a 6 N electric force</u>

F = 6 N

q = 2 C

Therefore,

E = 6 N/2 C = 3 N/C

E) <u>A 3 C charge acted on by a 3 N electric force</u>

F = 3 N

q = 3 C

Therefore,

E = 3 N/3 C = 1 N/C

F) <u>A 4 C charge acted on by a 2 N electric force</u>

F = 2 N

q = 4 C

Therefore,

E = 2 N/4 C = 0.5 N/C

The highest field is 3 N, which is found in part D.

<u>A 2 C charge acted on by a 6 N electric force</u>

3 0
4 years ago
Me - HS_SCLPhysical Science,
nalin [4]

Answer:

What's the question

Explanation:

3 0
4 years ago
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