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3 years ago

Compare and contrast infrasonic and ultrasonic vibrations

Physics

1 answer:

Olegator [25]3 years ago

8 0

Answer:

Explanation:

Ultrasonic waves are acoustic waves that are so high in frequency that humans can't hear them; however, infrasonic waves are sound waves that are lower in frequency than what humans can hear. A subsonic wave is a wave that is traveling slower than the speed of sound and a supersonic waves travels faster

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The majority of earthquakes worldwide occur at all but one location. That is A)at tectonic plate boundaries.B)where sediments de

DENIUS [597]

Answer:b

Explanation:

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3 years ago

A stone is dropped at t = 0. A second stone, with twice the mass of the first, is dropped from the same point at t = 181 ms. How

lara [203]

Answer:

the center of mass is 316,670m bellow the release point.

Explanation:

First, we must find the distance at which the objects are in time t = 360s

We will use the formula for vertical distance in free fall

$h=v_{0}t+\frac{1}{2} gt^2$

$v_{0}$ is the initial velocity, is 0 for both stones since they were just dropped.

g is acceleration of gravity and t is time ( $g=9.81m/s^2$ )

At $t=360s$ the first stone has been falling for the entire 360 seconds, its position h1 is:

$h_{1}=\frac{1}{2} (9.82m/s^2)(360s^2)=635,688m$

And at 360 seconds the second stone has been fallin for $t= 360s -181 s = 179s$ , so its position h2 is:

$h_{2}=\frac{1}{2} (9.81m/s^2)(179)^2=157,161.1m$

And finally using the equation for the center of mass:

$CM=\frac{m_{1}h_{1}+m_{2}h_{2}}{m_{1}+m_{2}}$

We know that the mass of the second stone is twice the mass of the first stone so:

$m_{1}=m\\m_{2}=2m$

replacing these values in the equation for the center of mass

$CM=\frac{mh_{1}+2mh_{2}}{m+2m}$

$CM=\frac{m(h_{1}+2h_{2})}{3m}=\frac{h_{1}+2h_{2}}{3}$

Finally, replacing the values we found fot h1 and h2:

$CM=\frac{635,688m+2(157,161.1m)}{3}=316,670m$

the center of mass is 316,670m bellow the release point.

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4 years ago

Ted wants to hang a wall clock on the wall by using a string. If the mass of the wall clock is 0.250 kilograms, what should be t

Ahat [919]

The clock is pulling the force towards earth's center because of gravity.
That force is equal to:
F = m*g where g is gravitational acceleration.

We will take that g = 9.81m/s^2

Now:
F = 0.25 * 9.81 = 2.4525 N

The string needs to sustain that force, therefore minimum Force that string has to be able to sustain is:
2.4525 N

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3 years ago

Read 2 more answers

A racing car has a mass of 1525kg. What is its kinetic energy if it has a speed of 108km/h

Reptile [31]

E = 1/2 m v^2

108000m /3600 = 30m/s

E = 1525 * 0.5 * 30 = 22875 J

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3 years ago

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4 years ago