Explanation:The input force is the force that is applied by the user of the lever. The output force is the force applied by the lever to an object.
Answer: A 100-lb child stands on a scale while riding in an elevator. Then, the scale reading approaches to 100lb, while the elevator slows to stop at the lowest floor
Explanation: To find the correct answer, we need to know more about the apparent weight of a body in a lift.
<h3>What is the apparent weight of a body in a lift?</h3>
- Consider a body of mass m kept on a weighing machine in a lift.
- The readings on the machine is the force exerted by the body on the machine(action), which is equal to the force exerted by the machine on the body(reaction).
- The reaction we get as the weight recorded by the machine, and it is called the apparent weight.
<h3>How to solve the question?</h3>
- Here we have given with the actual weight of the body as 100lbs.
- This 100lb child is standing on the scale or the weighing machine, when it is riding .
- During this condition, the acceleration of the lift is towards downward, and thus, a force of ma .
- There is also<em> mg </em>downwards and a normal reaction in the upward direction.
- when we equate both the upward force and downward force, we get,
i.e. during riding the scale reads a weight less than that of actual weight.
- When the lift goes slow and stops the lowest floor, then the acceleration will be approaches to zero.
Thus, from the above explanation, it is clear that ,when the elevator moves to the lowest floor slowly and stops, then the apparent weight will become the actual weight.
Learn more about the apparent weight of the body in a lift here:
brainly.com/question/28045397
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Answer: Easy it's 20 miles per second
Explanation:
500 ÷ 25 is equal to 20 miles per second aka 20 × 25 is equal to 500.
Answer:
Explanation:
<u>Properties of a virtual image:</u>
1. Image formed cannot be projected or focused on a screen.
2. The distance of the object to the mirror is the same as the distance from the image to the mirror.
3. The size of the image formed is the same as the size of the object.
4. The image formed is laterally inverted. That is the right becomes left and vice versa.
5. The image is upright.
<u>Properties of a real image:</u>
1. Image formed can be projected on a screen.
2, The distance from the image to the mirror is not the same as the distance from the object to the mirror.
3. The size of the image is not the same as the size of the object.
4. Image formed is upside down.
A ) The first ball:
h = v o * t - g t² / 2
19.6 = 14.7 t + 9.8 t²/2
4.9 t² + 14.7 t - 19.6 = 0
t 1/2 = (-14.7 +/- √216.09+384.16 ) / 9.8 = 9.8/9.8 = 1 s
The second ball:
v = v o - g t
0 = 14.7 - 9.8 t
9.8 t = 14.7
t = 1.5 ( upward )
h = 19.6 + 14.7 - 9.8 * 1.5 = 30.625 m
30.625 = 9.8 * t²/2
t² = 6.25
t = 2.5 s ( downward )
1.5 s + 2.5 s = 4 s
The difference: 4 s - 1 s = 3 s.
B ) The first ball:
v = v o + g t = 14.7 + 9.8 * 1 = 24.5 m/s
The second ball:
v = g * t = 9.8 * 3 = 24.5 m/s
C ) d 1 = 14.7 * 0.8 + 9.8 * 0.8²/2 = 11.76 + 3.136 = 14.896 m
d 2 = 14.7 * 0.8 - 9.8* 0.8²/2 = 11.76 - 3.136 = 8.624 m
d 1 + d 2 = 14.896 + 8.624 = 23.52 m