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valkas [14]
3 years ago
11

What is the magnitude momentum of a 2 kg body that moves with a speed of 3 m/s? (1 point)

Physics
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

<h2>D</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 2 kg

velocity/speed = 3 m/s

We have

momentum = 2 × 3 = 6

We have the final answer as

<h3>6 kg.m/s</h3>

Hope this helps you

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A solid metal sphere of diameter D is spinning in a gravity-free region of space with an angular velocity of ωi. The sphere is s
Leona [35]

Answer:

0.6

Explanation:

The volume of a sphere = \frac{4}{3} \pi (\frac{D}{2})^3

Therefore \pi * r^2 * (\frac{D}{2} ) = \frac{4}{3} \pi (\frac{D}{2})^3

r of the disc = 1.15(\frac{ D}{2} )

Using conservation of angular momentum;

The M_i of the sphere = \frac{2}{5} m \frac{D}{2}^2

M_i of the disc = m*\frac{   \frac{1.15*D}{2}^2 }{2}

\frac{wd}{ws} = \frac{\frac{2}{5}m * \frac{D}{2}^2}{  m * \frac{(\frac{`.`5*D}{2})^2 }{2} }

= 0.6

5 0
3 years ago
Two convex lenses are placed 15 cm apart. The left lens has a focal length of 10 cm, and the right lens a focal length of 5 cm.
Minchanka [31]

Answer:

The image distance from right lens is 2.86 cm and image is real.

Explanation:

Given that,

Focal length of left lens = 10 cm

Focal length of right lens = 5 cm

Distance between the lenses d= 15 cm

Object distance = 50 cm

We need to calculate the image distance from left lens

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{10}-\dfrac{1}{-50}

\dfrac{1}{v}=\dfrac{3}{25}

v=8.33\ cm

We need to calculate the image distance from right lens

The object distance will be

u = 15-8.33 = 6.67\ cm

Using formula of lens

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{5}-\dfrac{1}{-6.67}

\dfrac{1}{v}=\dfrac{1167}{3335}

v=2.86\ cm

The image is real.

Hence, The image distance from right lens is 2.86 cm and image is real.

4 0
3 years ago
21. A person standing 49.5m from the foot of a cliff claps his hands and hears an echo 0.3
777dan777 [17]

Answer:

330 m/s

Explanation:

The sound wave has to travel TO the cliff AND back = 2 * 49.5 = 99 m

magnitude of velocity =  distance / time = 99m / .3 s = 330 m/s

5 0
2 years ago
Phase, color, and ductility are all examples of what type of property?
Mama L [17]
Physical properties.
7 0
3 years ago
An ant moves at 5 cm/s. It takes her 2 minutes to cross a road. How wide is the road?
Alecsey [184]

so as this ant moves

5 cm every second you multiply 5 by 120 (60 per minute as there are 60 seconds in a minute)

this is 600 cm

or

6 meters

4 0
3 years ago
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