All categories

3 years ago

500.0 ml of 0.110 m naoh is added to 535 ml of 0.250 m weak acid (ka = 6.37 × 10-5. what is the ph of the resulting buffer?

1 answer:

7 0

The main formulas are pH=pKa + log(Base/Acid) and pKa = -log(Ka)
so firstly, we must find the value of pKa,
Ka=6.37 x 10 ^-5, and then logKa= log (6.37 . 10^-5)= -9.66, so -logKa= +9.66=Ka
next let's find log(Base/Acid)
for that the concentration of NaOH is [NaOH] = 500.0 x 0.110 / 500+535 =0.053M, the concentration of the Acid is [Acid] =535*0.25 / 500+535 =0.12M, so its difference is [Acid]-[NaOH] = 0.12-0.053=0.07
so pH=pKa + log(Base/Acid)= 9.66 + log(0.053 / 0.07)= 9.66-0.36=9.29 
so pH=9.29.

You might be interested in

Suppose you have a solution that is either an acid or a base. It doesn’t react with any metals. Is the pH of the solution more l

OverLord2011 [107]

Its more likely to be a four

4 0

3 years ago

vodka [1.7K]

In my opinion the answer is identical

3 0

2 years ago

Read 2 more answers

PLEASE HELP ME, 20 POINTS

Marrrta [24]

Explanations:

Question 1: Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.

I am unsure of Question 2. I don't think it is mole though.

Question 3: Boron in 25.00-30.00 g is B. or D., but 25.00 g would be C.

Question 4: 2.393 x 1024 atoms of Oxygen is 63.58 mole O. I don't know for sure, but I think this is correct.

I am NOT professional. There is a chance I am incorrect. Please reply to me if I've made a mistake.

4 0

2 years ago

When you take 10 grams of salt, and dissolve it in 25 grams of hot water what is the solubility

AURORKA [14]

Answer:

When salt is mixed with water, the salt dissolves because the covalent bonds of water are stronger than the ionic bonds in the salt molecules. ... Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together.

Explanation:

4 0

2 years ago

The size (radius) of an oxygen molecule is about 2.0 ×10−10m. Make a rough estimate of the pressure at which the finite volume o

belka [17]

Answer:

Explanation:

We can calculate the volume of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

volume=33.40×10⁻³⁰m³

Volume of oxygen molecule=33.40×10⁻³⁰m³

we know the ideal gas equation as:

PV=nRT

k=R/Na

R=k×Na

PV=n×k×Na×T

n×Na=N

PV=Nkt

p is pressure of gas

v is volume of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

p=12.39×10⁷Pascal

8 0

3 years ago