What I can’t understand I’m American
The formula of Iron(III) oxide is Fe2O3
In order to calculate the mass of iron in a given sample of iron(III) oxide, we must first know the mass percentage of iron in iron(III) oxide. This is calculated by:
[mass of iron in one mole of iron(III) oxide/ mass of one mole of iron(III) oxide] * 100
= [(moles of iron * Mr of iron) / (moles of Iron * Mr of Iron + moles of Oxygen * Mr of Oxygen)] * 100
= [(2 * 56) / (2 * 56 + 3 * 16)] * 100
= (112 / 160) * 100
= 70%
Thus, in a 100g sample, the weight of iron will be:
100 * 70%
= 70 grams
Hi there!
Thank you for choosing Brainly.
1 mole = 44.0095
So take that number and multiply it by 6.75.
You then get... 297.0641
Have a nice day.
~Brooke
Calcium (s) + h2o (i) -> carbon(oh)2 (AQ) +h(6)
well aq isnt a element.
Answer:
= 3.456 × 1011
(scientific notation)
= 3.456e11
(scientific e notation)
= 345.6 × 109
(engineering notation)
(billion; prefix giga- (G))
= 345600000000
(real number)
Explanation:
i dont know if its math or something else so here are your answers:)
