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Musya8 [376]
4 years ago
8

What is the equilibrium constant expression for the given system? CO(g) + 2H(2)(g) <-----> CH(3)OH(g)

Chemistry
1 answer:
Licemer1 [7]4 years ago
5 0

<u><em>Answer:</em></u>

  • Kc =  [CH3OH]  ÷  [CO][H2]∧2

<u><em>Explanation:</em></u>

                         CO(g) + 2H(2)(g) <-----> CH(3)OH(g)

  • Rate of forward reaction = Kf [CO][H2]∧2
  • Rate of reverse reaction = Kr [CH3OH]

At equlibrium

                      Rate of forward = rate of reverse

                       Kf [CO][H2]∧2   =   Kr [CH3OH]  

                                         Kf/Kr =    [CH3OH]  ÷  [CO][H2]∧2

                                              Kc =  [CH3OH]  ÷  [CO][H2]∧2

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