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Musya8 [376]
4 years ago
8

What is the equilibrium constant expression for the given system? CO(g) + 2H(2)(g) <-----> CH(3)OH(g)

Chemistry
1 answer:
Licemer1 [7]4 years ago
5 0

<u><em>Answer:</em></u>

  • Kc =  [CH3OH]  ÷  [CO][H2]∧2

<u><em>Explanation:</em></u>

                         CO(g) + 2H(2)(g) <-----> CH(3)OH(g)

  • Rate of forward reaction = Kf [CO][H2]∧2
  • Rate of reverse reaction = Kr [CH3OH]

At equlibrium

                      Rate of forward = rate of reverse

                       Kf [CO][H2]∧2   =   Kr [CH3OH]  

                                         Kf/Kr =    [CH3OH]  ÷  [CO][H2]∧2

                                              Kc =  [CH3OH]  ÷  [CO][H2]∧2

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There are 10 hydrogen atoms that bind and there are 2 pairs of free electrons in the non-binding O atom

<h3>Further explanation</h3>

Aldehydes are alkane-derived compounds containing carbonyl groups (-CO-) where one bond binds to an alkyl group while another binds to a hydrogen atom.

The general structure is R-CHO with the molecular formula :

\large{\boxed{\boxed{\bold{C_nH_{2n}O}}}

Naming is generally the same as the alkane by replacing the suffix with -al

Butanal or butyraldehyde is an aldehyde which has 4 C atoms

Inside the structure there are 3 atoms involved in bonding:

  • 1. Atom C with 4 valence electrons, requires 4 electrons to reach the octet
  • 2. Atom O with 6 valence electrons, requires 2 electrons to reach the octet
  • 3. Atom H with 1 valence electron, requires 1 electron to reach a duplet

In describing Lewis's structure the steps that can be taken are:

  •  1. Count the number of valence electrons from atoms in a molecule
  • 2. Give each bond a pair of electrons
  • 3. The remaining electrons are given to the atomic terminal so that an octet is reached
  • 4. The remaining electrons that still exist in the central atom
  • 5. If the central atom is not yet octet, free electrons are drawn to the central atom to form double bonds

In the Butanal structure (C₄H₈O) there is 1 double bond of the functional group (-CHO) between the C atom and the O atom

<h3>Learn more: </h3>

Adding electron dots

brainly.com/question/6085185

Ionic bonding

brainly.com/question/1603987

Formal charge

brainly.com/question/7190235

 

Keywords: butanal, aldehyde, Lewis structure, a valence electron

8 0
4 years ago
Read 2 more answers
Molecules at a higher temperature have _______ kinetic energy, speed, and momentum compared to molecules at a lower temperature.
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Molecules at a higher temperature have higher/more kinetic energy, speed, and momentum compared to molecules at a lower temperature.

Explanation:

8 0
2 years ago
Sodium metal and chlorine gas are combined in a reaction to produce sodium chloride also known as table salt. What are the react
m_a_m_a [10]

Answer: sodium metal and chlorine gas

Explanation:

6 0
3 years ago
Identify the change in state that does NOT have an increase in entropy. Identify the change in state that does NOT have an incre
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Answer:

condensing water

Explanation:

Entropy refers to the level of disorderliness in a system. The entropy of liquids is greater than that of solids. The entropy of gases is greater than that of liquids.

A process of physical change involving a change of state from solid to liquid or liquid to gas is accompanied by increase in entropy.

However, a change of state involving a change from liquid to solid or gas to liquid is accompanied by decrease in entropy.

Hence, steam condensing to water leads to decrease and not increase in entropy of the system.

4 0
3 years ago
2. If 1.204 X 1024 atoms of sodium is 20% of the total sodium atoms in sodium
GuDViN [60]

Answer:

584.2 g

Explanation:

Hello there!

In this case, since we know the 20% of the atoms correspond to sodium, we can compute the total atoms as shown below:

\frac{1.204 x10^{24}}{0.2}=6.02x10^{24}atoms

Which are also equal to 1 mol and the Avogadro's number of sodium chloride with a molar mass of 58.44 g/mol; thus, the grams of salt turn out to be:

6.02x10^{24}atoms*\frac{1mol}{6.022x10^{23}atoms} *\frac{58.44g}{1mol}\\\\=584.2g

Best regards!

3 0
3 years ago
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