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butalik [34]
3 years ago
8

Draw the lewis structure for butanal, which has the condensed formula ch3(ch2)2cho. show all hydrogen atoms and lone pairs of el

ectrons.

Chemistry
2 answers:
sergejj [24]3 years ago
8 0

There are 10 hydrogen atoms that bind and there are 2 pairs of free electrons in the non-binding O atom

<h3>Further explanation</h3>

Aldehydes are alkane-derived compounds containing carbonyl groups (-CO-) where one bond binds to an alkyl group while another binds to a hydrogen atom.

The general structure is R-CHO with the molecular formula :

\large{\boxed{\boxed{\bold{C_nH_{2n}O}}}

Naming is generally the same as the alkane by replacing the suffix with -al

Butanal or butyraldehyde is an aldehyde which has 4 C atoms

Inside the structure there are 3 atoms involved in bonding:

  • 1. Atom C with 4 valence electrons, requires 4 electrons to reach the octet
  • 2. Atom O with 6 valence electrons, requires 2 electrons to reach the octet
  • 3. Atom H with 1 valence electron, requires 1 electron to reach a duplet

In describing Lewis's structure the steps that can be taken are:

  •  1. Count the number of valence electrons from atoms in a molecule
  • 2. Give each bond a pair of electrons
  • 3. The remaining electrons are given to the atomic terminal so that an octet is reached
  • 4. The remaining electrons that still exist in the central atom
  • 5. If the central atom is not yet octet, free electrons are drawn to the central atom to form double bonds

In the Butanal structure (C₄H₈O) there is 1 double bond of the functional group (-CHO) between the C atom and the O atom

<h3>Learn more: </h3>

Adding electron dots

brainly.com/question/6085185

Ionic bonding

brainly.com/question/1603987

Formal charge

brainly.com/question/7190235

 

Keywords: butanal, aldehyde, Lewis structure, a valence electron

IgorC [24]3 years ago
3 0

There are \boxed{10} hydrogens and \boxed2 lone pairs in the Lewis structure of butanal. (Refer structure in the attached image)

Further Explanation:

The bonding between the different atoms in covalent molecules is shown by some diagrams known as the Lewis structures. These also show the presence of lone pairs in the molecule. These are also known as Lewis dot diagrams, electron dot diagrams, Lewis dot structures or Lewis dot formula. In covalent compounds, the geometry, polarity, and reactivity are predicted by these structures.

Lewis structure of {\mathbf{C}}{{\mathbf{H}}_{\mathbf{3}}}{\left( {{\mathbf{C}}{{\mathbf{H}}_{\mathbf{2}}}} \right)_{\mathbf{2}}}{\mathbf{CHO}} :

The total number of valence electrons of {\text{C}}{{\text{H}}_3}{\left({{\text{C}}{{\text{H}}_2}}\right)_2}{\text{CHO}} is calculated as,

Total valence electrons = [(4) (Valence electrons of C) + (8) (Valence electrons of H) + (1) (Valence electrons of O)]

\begin{aligned}{\text{Total valence electrons}}\left({{\text{TVE}}}\right)&= \left[{\left({\text{4}}\right)\left({\text{4}}\right)+\left({\text{8}}\right)\left({\text{1}}\right)+\left({\text{1}} \right)\left({\text{6}}\right)}\right]\\&=30\\\end{gathered}

The general formula of aldehyde functional group is {\text{R}} - {\text{CHO}} . The given molecule has also the same formula and therefore the given molecule is an aldehyde.

In {\text{C}}{{\text{H}}_3}{\left({{\text{C}}{{\text{H}}_2}}\right)_2}{\text{CHO}} , the total number of valence electrons is 30. Here, {{\text{C}}_1}  forms two single bonds, one with a hydrogen atom and other with {{\text{C}}_2} . It also forms one double bond with an oxygen atom. {{\text{C}}_2}  forms two single bonds with other two hydrogen atoms and two single bonds with {{\text{C}}_1} and {{\text{C}}_3}  separately. {{\text{C}}_3}  forms two single bonds with two hydrogen atoms and two single bonds with {{\text{C}}_2} and {{\text{C}}_4} separately. {{\text{C}}_4} forms one single bond with {{\text{C}}_3}  and three single bonds with three hydrogen atoms. Oxygen forms one double bond with {{\text{C}}_1} . Each hydrogen forms a single bond with carbon atoms and therefore 26 electrons are utilized. The remaining four are present in the form of lone pair on the oxygen atom. (Refer to the structure in the attached image)

Learn more:

1. Molecular shape around each of the central atoms in the amino acid glycine: brainly.com/question/4341225

2. How many molecules will be present on completion of reaction?: brainly.com/question/4414828

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Molecular structure and chemical bonding

Keywords: Lewis structure, valence electrons, butanal, CH3(CH2)2CHO, single bonds, double bonds, carbon atom, hydrogen atom, oxygen atom, valence electrons.

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Anestetic [448]

The image of the bonds are missing, so i have attached it.

Answer:

A) - Sigma bond

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- None

B) - Sigma and pi bond

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Explanation:

A) For compound 1;

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Ethane, C2H6, burns in oxygen. First write a balanced equation for this combustion reaction. What mass of oxygen, in grams, is r
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We need 50.6 grams of oxygen

Explanation:

Step 1: Data given

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Step 2: The balanced equation

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Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 13.6 grams / 30.07 g/mol

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Step 4: Calculate moles oxygen

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

For 0.452 moles ethane we need 3.5*0.452 = 1.582 moles O2

Step 5: Calculate mass O2

Mass O2 = moles O2 * molar mass O2

Mass O2 = 1.582 moles * 32.0 g/mol

Mass O2 =  50.6 grams

We need 50.6 grams of oxygen

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