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Alex787 [66]
3 years ago
7

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. when 18.0 g of carbon were burned in the presence of

62.3 g of oxygen, 14.3 g of oxygen remained unreacted. what mass of carbon dioxide was produced?
Chemistry
1 answer:
zavuch27 [327]3 years ago
7 0
C + O2 --> CO2

18g C = 18/12.01 = 1.49 moles (Limiting Reagent) 
62.3-14.3 = 48g oxygen that reacted 
48g O = 3 moles 
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Arlecino [84]
One way you can work out the rate of reaction is by the amount of product that is produced to time. This can also be done with heat and time.

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8 0
3 years ago
Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:
posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of HNO_3 = \frac{15.5g}{63g/mol\times 9.5L}=0.026M

Equilibrium concentration of NO = \frac{16.6g}{30g/mol\times 9.5L}=0.058M

Equilibrium concentration of NO_2 = \frac{22.5g}{46g/mol\times 9.5L}=0.051M

Equilibrium concentration of H_2O = \frac{189.0g}{18g/mol\times 9.5L}=1.10M

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c  

For the given chemical reaction:

2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)

The expression for K_c is written as:

K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}

K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}

K_c=3.72

Thus  the value of the equilibrium constant Kc for this reaction is 3.72

5 0
2 years ago
When potassium chromate, k2cro4, dissolves in water, what ions are produced?
Alexandra [31]
When potassium chromate dissolves in water, the ions that are produced are potassium and chromate.

This can be expressed as follows:
Potassium chromate in water will give the following ions:
<span>2K+ + CrO4^2- </span>
7 0
3 years ago
Need answer asap, will give brainliest!!!
Pavlova-9 [17]

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Molecules consist of multiple atoms put together to create a new form.

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<em><u>Question</u></em>

<em><u>What </u></em><em><u>does </u></em><em><u>it </u></em><em><u>mean </u></em><em><u>to </u></em><em><u>optimize</u></em><em><u> </u></em><em><u>a </u></em><em><u>solution?</u></em>

<em><u>To find out best possible solution for a given problem within the given constraint is generally termed as optimization</u></em>

<em><u>How </u></em><em><u>are </u></em><em><u>solution</u></em><em><u> </u></em><em><u>optimize</u></em><em><u> </u></em><em><u>?</u></em>

<em><u>To solve an optimization problem, begin by drawing a picture and introducing variables. Find an equation relating the variables. Find a function of one variable to describe the quantity that is to be minimized or maximized. Look for critical points to locate local extrema.</u></em>

6 0
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