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Alex787 [66]
3 years ago
7

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. when 18.0 g of carbon were burned in the presence of

62.3 g of oxygen, 14.3 g of oxygen remained unreacted. what mass of carbon dioxide was produced?
Chemistry
1 answer:
zavuch27 [327]3 years ago
7 0
C + O2 --> CO2

18g C = 18/12.01 = 1.49 moles (Limiting Reagent) 
62.3-14.3 = 48g oxygen that reacted 
48g O = 3 moles 
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O<br> Plz answer this plz plz plz
saul85 [17]

Answer:

Q1. C

Q2 and Q3 are correct.

Explanation:

Since F=ma, and the force is a constant,

for the greatest acceleration, the mass of the ball must be the least.

Thus ball C has the greatest acceleration.

Let's check:

A) F=ma

a=F/m

a= F/68

B) a=F/72

C) a= F/64 (✓)

The smaller the denominator, the larger the value of a.

(Think: 1/2 >1/3)

3 0
3 years ago
What are three reasons why a population might change?
Tom [10]
If people have children, If people die, and if there is a fire or volcanic eruption.

4 0
3 years ago
A bond between a nonmetal and a nonmetal is called a(n)
Pani-rosa [81]

Answer:

answer: B

Explanation:

becaucse it is B

7 0
2 years ago
Read 2 more answers
Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
GrogVix [38]

Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

8 0
2 years ago
Necesito ayuda porfavor
AlexFokin [52]

Answer:

thank for the points ❤️

Explanation:

pa breinlyest po

8 0
3 years ago
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