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Vitek1552 [10]
3 years ago
13

A scientist is examining an unknown solid. which procedure would most likely help determine a chemical property of the substance

​
Physics
1 answer:
asambeis [7]3 years ago
7 0

Answer:

exposing it to a flame to see if it catches on fire

Explanation:

A chemical property is when the matter changes into a different substance. This is true when you expose it to a flame because if a substance is burned, it will change into a new substance. All the other options are examples of physical changes.

-I also took the quiz and got 100%

Hope this helps!

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If a velocity is positive which would most likely yield a negative acceleration
Aleksandr [31]

Answer:

A time that is less than half an hour

Explanation:

it says velocity is positive so it would yield to a negative acceleration

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3 years ago
كرة كتلتها و 200 مربوطة بنهاية خيط طوله m 1 تتحرك حركة دائرية منتظمة في مسار دائري
Vesna [10]
Asalam a lekum my brother
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3 years ago
Tarzan is running with a horizontal velocity, along level ground. While running, he encounters a 2.21 m vine of negligible mass,
Lena [83]

Answer:

a) a_c = 1.09m/s^2

b) T = 720.85N

Explanation:

With a balance of energy from the lowest point to its maximum height:

m*g*L(1-cos\theta)-1/2*m*V_o^2=0

Solving for V_o^2:

V_o^2=2*g*L*(1-cos\theta)

V_o^2=2.408

Centripetal acceleration is:

a_c = V_o^2/L

a_c = 2.408/2.21

a_c = 1.09m/s^2

To calculate the tension of the rope, we make a sum of forces:

T - m*g = m*a_c

Solving for T:

T =m*(g+a_c)

T = 720.85N

3 0
4 years ago
PLEEEASEEEEEE HELPPPPP PLEASEEEEEEEEEE science
valkas [14]

Answer:

A

Explanation:

transverse wave

Hope this helps you!

7 0
3 years ago
A youngs interference experiment is performed with blu-green argon laser light .The slits is 0.5mm, and the screen is located 3,
hammer [34]

Answer:

515 nm

Explanation:

The equation that gives the position of the maxima (bright fringes) in the interference pattern produced on a distant screen by the diffraction of light through two slits is

y=\frac{m\lambda D}{d}

where

y is the distance of the maximum (bright fringe) from the central maximum

m is the order of the maximum

\lambda is the wavelength of the light used

D is the distance of the screen

d is the separation between the slits

In this problem we have:

d=0.5 mm = 0.5\cdot 10^{-3} m is the separation between the slits

D = 3.30 m is the distance of the screen

m = 1 (we are analyzing the 1st bright fringe)

y=3.40 mm = 3.40\cdot 10^{-3} m is the distance of the 1st bright fringe from the central maximum

Solving for \lambda, we find the wavelength of the light used:

\lambda=\frac{yd}{mD}=\frac{(3.40\cdot 10^{-3})(0.5\cdot 10^{-3})}{(1)(3.30)}=5.15\cdot 10^{-7} m = 515 nm

6 0
3 years ago
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