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Phantasy [73]
3 years ago
13

A 17,000-kg airplane lands with a speed of 82 m/s on a stationary aircraft carrier deck that is 115 m long. find the work done b

y nonconservative forces in stopping the plane
Physics
1 answer:
zepelin [54]3 years ago
3 0
In physics<span>, a force is said to do </span>work if, when acting, there is a displacement of the point of application in the direction of the force. <span>Nonconservative force for this question refers to FRICTIONAL force. </span>

<span>By conservation of energy, </span>

<span>Work done by Frictional force = Kinetic energy = 1/2(17000)(82)^2 = 57MJ </span>
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Which of the following is not an SI unit?
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Answer:

Pound

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8 0
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Acceleration depends on which two factors?
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Answer:

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2 years ago
A ball is launched at 24m/s at a 45 degree angle as shown. What is the horizontal component of the velocity (Vx)? (don't include
zaharov [31]

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Vx = Vo * cos α

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umka2103 [35]

Answer:

70 N

21°

1.1 m/s²

Explanation:

Draw a free body diagram of the block.  There are three forces:

Weight pulling straight down

Normal force pushing perpendicular to the incline

Friction force pushing parallel to the incline

Part 1

Sum the forces in the perpendicular direction:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

The block is at rest, so F = N μs:

F = N μs

F = mg μs cos θ

F = (20 kg) (9.8 m/s²) (0.38) (cos 19°)

F = 70 N

Part 2

Sum the forces in the parallel direction (down the incline is positive):

∑F = ma

mg sin θ − F = 0

mg sin θ = N μs

mg sin θ = mg μs cos θ

tan θ = μs

θ = atan μs

θ = atan 0.38

θ = 21°

Part 3

Sum the forces in the parallel direction (this time, acceleration is not 0).

∑F = ma

mg sin θ − F = ma

mg sin θ − N μk = ma

mg sin θ − mg μk cos θ = ma

a = g (sin θ − μk cos θ)

a = (9.8 m/s²) (sin 24° − 0.32 cos 24°)

a = 1.1 m/s²

4 0
3 years ago
Read 2 more answers
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