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Semenov [28]
3 years ago
5

Suppose a magnetic reversal accoured today .

Physics
2 answers:
alex41 [277]3 years ago
8 0

Answer:

they both different mario

Explanation:

Brut [27]3 years ago
3 0
They would have the magnetic parts of the rocks oriented differently. This leaves a trace that allow scientists to find out how often this actually happens (as far as I remember, it's on average once in 800 000 years)
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A basketball player jumped straight up to grab a rebound. If she was in the air for 0.80 second, how high did she jump?
Kazeer [188]
-- She went up for 0.4 sec and down for 0.4 sec.

-- The vertical distance traveled in gravity during ' t ' seconds is

                   D  =  (1/2)  x  (g)  x  (t)²

                       = (1/2) (9.8 m/s²) (0.4 sec)²

                       =    (4.9 m/s²)  x  (0.16 s²)

                       =      0.784 meter        ( B )
4 0
3 years ago
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You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand at 30 m/s. What is the kinetic energy (KE) of the volley
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awnser :

Explanation:

8 0
2 years ago
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A device that converts mechanical energy into electricity is a
IgorLugansk [536]

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An electric generator is a device that converts a form of energy into electricity.

Explanation:

7 0
3 years ago
If 2.2 lbs = 1.0 kg, and Megan Progress weighs 130 lbs, what is her weight in newtons?
Dafna11 [192]

Answer:

Force = 2802.8 Newton

Explanation:

Given the following data;

Mass = 130 lbs

But, 2.2 lbs = 1.0 kg

130 lbs to kg = 130 * 2.2 = 286 kg

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To find the force in Newton;

Force = mass * acceleration due to gravity

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8 0
3 years ago
A tall cylinder contains 20 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t
Zanzabum

Answer:

Pressure, P = 3724 Pa

Explanation:

Given that,

Depth of water, h_w=20\ cm =0.2\ m

Depth of oil, h_o=40-20=20\ cm=0.2\ m

The density of water, d_w=1000\ kg/m^3

The densinty of oil, d_o=900\ kg/m^3

We need to find the gauge pressure at the bottom of the cylinder. So, total pressure is equal to :

P=d_wgh_w+d_ogh_o\\\\P=(d_wh_w+d_oh_o)g\\\\P=(1000\times 0.2+900\times 0.2)\times 9.8\\\\P=3724\ Pa

So, the gauge pressure at the bottom of the cylinder is 3724 Pa.

3 0
3 years ago
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