Responder:
20πrads ^ -1; 24πrads ^ -1; 0,1 seg; 10 Hz
Explicación:
Dado lo siguiente:
Radio (r) del círculo = 120 cm
600 revoluciones por minuto en radianes por segundo
(600 / min) * (2π rad / 1 rev) * (1min / 60seg)
(1200πrad / 60sec) = 20π rad ^ -1
Velocidad angular (w) = 20πrads ^ -1
Velocidad lineal = radio (r) * velocidad angular (w)
Velocidad lineal = (120/100) * 20πrad
Velocidad lineal = 1.2 * 20πrads ^ -1 = 24πrads ^ -1
C.) Período (T):
T = 2π / w = 2π / 20π = 0.1 seg
D.) Frecuencia (f):
f = 1 / T = 1 / 0.1
1 / 0,1 = 10 Hz
All of the above as it states that "<span>a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers"</span>
First, we convert kcal to joules:
1 kcal = 4.184 kJ
475 kcal = 1987.4 kJ
Now, calculating the change in internal energy:
ΔU = Q + W; where Q is the heat supplied to the system and W is the work done on the system.
ΔU = -500 + 1987.4
ΔU = 1487.4 kJ
1200
-------=171 miles per hour
7
We can determine a planet's orbital period and separation from its star using any detection method. The transit method can yield sizes, whereas the astrometric and doppler approaches can provide minimum masses.
We can calculate average density by combining the transit and doppler approaches. Numerous physical properties, including the semi-major axis, stellar mass, star radius, planet radius, eccentricity, and inclination, are calculated from these observable data. The mass of the planet is also calculated using the star's combined radial velocity readings.
List briefly the planetary characteristics that, in theory, can be detected with the present detection techniques. We can determine a planet's orbital period and separation from its star using any detection method. The transit method can yield sizes, whereas the astrometric and doppler approaches can provide minimum masses.
To know more about orbital period
brainly.com/question/28068951
#SPJ4
