Answer:
109.94 g/mol
Explanation:
Li is 6.94 and there's 2 of those = 13.88
1 S = 32.06
4 O = 63.996
Add all of those together to get 109.936 round to 109.94
Answer:
-179.06 kJ
Explanation:
Let's consider the following balanced reaction.
HCl(g) + NaOH(s) ⟶ NaCl(s) + H₂O(l)
We can calculate the standard enthalpy change for the reaction (ΔH°r) using the following expression.
ΔH°r = 1 mol × ΔH°f(NaCl(s)) + 1 mol × ΔH°f(H₂O(l)) - 1 mol × ΔH°f(HCl(g)) - 1 mol × ΔH°f(NaOH(s))
ΔH°r = 1 mol × (-411.15 kJ/mol) + 1 mol × (-285.83 kJ/mol) - 1 mol × (-92.31 kJ/mol) - 1 mol × (-425.61 kJ/mol)
ΔH°r = -179.06 kJ
Answer : The correct answer is 2.36 mol of gold
1 mole of any element have 6.022 x 10²³ number of atoms ( Avogadro's number).
So the formula relating mole and number of atoms is given as :
Plugging value in formula :
Mole of gold = 2.36 mol
Yes I can do in organic chem
