Let p---------------> is the perimeter of the base s--------------> is the slant height ba-----------> is the area of the base la-----------> is the lateral area
we know that [surface area of the pyramid]=area of the base+perimeter of the base*slant height/2 so [surface area of the pyramid]=ba+p*s/2 la=p*s/2 [surface area of the pyramid]=ba+la
the answer is surface area=ba+p*s/2 surface area=ba+la
