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3 years ago

7

When an oxygen atom forms an ion, it gains two electrons. What is the electrical charge of the oxygen ion?

1 answer:

Damm [24]3 years ago

7 0

The oxygen atom, before it gains these two electrons, has a neutral charge, meaning that it has as many protons as electrons. After it gains 2 electrons, it has 2 more electrons than protons. Each electron has a charge of -1, so the whole molecule will have a charge of -2. The correct answer is a)!

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In a particular case of Compton scattering, a photon collides with a free electron and scatters backwards. The wavelength after

mafiozo [28]

Answer:

hence initial wavelength is $\lambda =4.86\times10^{-12}m$

Explanation:

shift in wavelength due to compton effect is given by

$\lambda ^{'}-\lambda =\frac{h}{m_{e}c}\times(1-cos\theta )$

λ' = the wavelength after scattering

λ= initial wave length

h= planks constant

m_{e}= electron rest mass

c= speed of light

θ= scattering angle = 180°

compton wavelength is

$\frac{h}{m_{e}c}= 2.43\times10^{-12}m$

$\lambda '-\lambda =2.43\times10^{-12}\times(1-cos\theta )$

$\lambda '-\lambda =2.43\times10^{-12}\times(1+1 )$ ( put cos 180°=-1)

also given λ'=2λ

putting values and solving we get

$\lambda =4.86\times10^{-12}m$

hence initial wavelength is $\lambda =4.86\times10^{-12}m$

4 0

4 years ago

The wheel on an upside-down bicycle moves through 18.0 rad in 5.39 s. What is the wheel’s angular acceleration if its initial an

Elden [556K]

Explanation:

Formula to calculate angular acceleration is as follows.

$\Delta (\theta) = \frac{1}{2} \alpha \Delta t^{2} + \omega_{1} \Delta t$

or, $\alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}$

Putting the given values into the above formula as follows.

$\alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}$

= $\frac{2(18.0 rad - 2.5 rad/s \times 5.30 s)}{(5.39)^{2}}$

= 0.326 $rad/s^{2}$

Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326 $rad/s^{2}$ .

5 0

4 years ago

A machine has an efficiency of 80%. How much work must be done on the machine so to make it do 50,000 J of output work?

Tamiku [17]

Work formula is Work=N∙M or Joule (J)

So you have the following given:

50 000 is the output work

.8 is the efficiency

if you input the given = 50000 = .8*J

To get the answer just divide 50000 by .8 to get the answer.

62,500 J is the amount of work to be done.

8 0

3 years ago

Read 2 more answers

You are doing a measurement to determine the conductance of an artificial membrane. The membrane is selectively permeable to Na

alex41 [277]

Answer:

What is the membrane's conductance = 2.47miuS

Explanation:

The detailed step and appropriate formula is as shown in the attached file.

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3 years ago

At 5.0 minutes, the temperature of the water reaches 100 °C. The volume of the water in the urn

serious [3.7K]

Answer:

fdvevddvevkejokef0jeovdlvkjeuiyv

Explanation:

ddf4edscd

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3 years ago