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DiKsa [7]
3 years ago
15

Describe how a convection cell is created in the mantle of the Earth.

Physics
2 answers:
g100num [7]3 years ago
4 0

Answer:

material near the core heats up, warming up the bottom layer of the mantle. Density begins to decrease due to particles moving more rapidly. The mantle's material then rises starting a convection current.

Explanation:

Sphinxa [80]3 years ago
3 0

Answer:

Convection currents within Earth's mantle form as material near the core heats up. As the core heats the bottom layer of mantle material, particles move more rapidly, decreasing its density and causing it to rise. The rising material begins the convection current.Feb 24, 2012

Explanation:

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Explain what parallel medium boundaries do to the path of the wave after it travels through both boundaries. (air and water)
Brilliant_brown [7]

Answer:

The boundaries cause the waves to change direction an effect called <u>refraction.</u>

Explanation:

When a wave crosses a boundary between different materials, the speed of the wave and its wavelength changes.When passing from air to water the two properties (speed and wavelength) decreases, and the wave is observed to change direction as it crosses the boundary between the two material.The bending of the wave is called refraction.

7 0
3 years ago
how does the size of objects impact the pull of gravity between Earth and a baseball thrown into the air
Reil [10]
it's how much it weighs and how much force is pushing on it like a egg if i drop it the weigh can cause it to break and how much force the gravity is pushing on it.
3 0
2 years ago
Read 2 more answers
(a) At what height above Earth’s surface is the energy required to lift a satellite to that height equal to the kinetic energy r
Nikitich [7]

Answer:

Explanation:

Gravitational Potential Energy at earth surface U_1=\frac{GM_em}{R_e}

Gravitational Potential Energy at height h is U_2=\frac{GM_em}{R_e+h}

Energy required to lift the satellite E_1=U_1-U_2

E_1=\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}

Now Energy required to orbit around the earth

E_2=\frac{1}{2}mv_{orbit}^2=\frac{GM_2m}{2(R_e+h)}

\Delta E=E_1-E_2

\Delta E=\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}-\frac{GM_2m}{2(R_e+h)}

E_1=E_2  (given)

\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}-\frac{GM_2m}{2(R_e+h)}=0

\frac{1}{R_e}-\frac{3}{2(R_e+h)}=0

h=\frac{R_e}{2}

h=3.19\times 10^6\ m

(b)For greater height E_1  is greater than E_2

thus energy to lift the satellite is more than orbiting around earth

4 0
3 years ago
A curve in a stretch of highway has radius R. The road is not banked in any way. The coefficient of static friction between the
adelina 88 [10]

Answer:

maximum possible velocity = \sqrt{ugR}

Explanation:

centripetal acceleration when the  car is going in the circle must be less than the maximum friction for the car to not slip.

centripetal acceleration \frac{mv^{2}}{r}

where v is the velocity of car and r is the radius of circle

maximum friction = umg

where u is the coefficient of static friction.

thereforeumg\geq \frac{mv^{2}}{R}

therefore maximum possible velocity = \sqrt{ugR}

6 0
3 years ago
Which pair of quantities includes one quantity that increases as the other decreases during simple harmonic motion?
11111nata11111 [884]

Kinetic energy and potential energy pair is the quantity in which one will increase then other will decrease

As we know that sum of kinetic energy and potential energy will always remain conserved

So here we will have

KE + PE = constant

so here as we move away from mean position the kinetic energy will decrease while at the same time potential energy will increase.

So the pair of potential energy and kinetic energy will satisfy the above condition

7 0
3 years ago
Read 2 more answers
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