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Ainat [17]
2 years ago
13

How are humans potentially vulnerable to some of these same chemicals? How are humans potentially vulnerable to some of these sa

me chemicals?
What should the government and/or industry do about these emerging contaminants?

What can you do to make water safer for yourself, your community, and the fish?
Physics
1 answer:
Svetradugi [14.3K]2 years ago
6 0
The 5 major unit processes include chemical coagulation, flocculation, sedimentation, filtration, and disinfection (described below). There are chemicals added to the water as it enters the various treatment processes.
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Who’s has bigger cross sectional area capillaries or aorta?
Natalka [10]

Answer:

Even though the cross-sectional area of each capillary is extremely small compared to that of the large aorta, the total cross-sectional area of all the capillaries added together is about 1,300 times greater than the cross-sectional area of the aorta because there are so many capillaries

Explanation:

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3 years ago
is it true that the composition of the atmosphere changes every few kilometers as you move away from earth
laiz [17]
Yes,it's true ok? So how have you been doing
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True or False<br><br> The greater the speed of an object, the less kinetic energy it possesses.
Anettt [7]
That is true because if the object is moving at Forceful speeds than it will lose more of its kinetic energy
3 0
3 years ago
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Water flows straight down from an open faucet. The cross-sectional area of the faucet is 2.4 × 10-4m2 and the speed of the water
Ksenya-84 [330]

To solve this problem it is necessary to apply the continuity equations in the fluid and the kinematic equation for the description of the displacement, velocity and acceleration.

By definition the movement of the Fluid under the terms of Speed, acceleration and displacement is,

v_2^2 = v_1^2 + 2gh

Where,

V_i = Velocity in each state

g= Gravity

h = Height

Our values are given as,

A_1 = 2.4*10^{-4} m^2

v_1 = 0.8 m/s

h = 0.11m

Replacing at the kinetic equation to find V_2 we have,

v_2 = \sqrt{v_1^2 + 2gh}

v_2 = \sqrt{(0.8 m/s)^2 + 2(9.80 m/s2)(0.11 m)}

v_2= 1.67 m/s

Applying the concepts of continuity,

A_1v_1 = A_2v_2

We need to find A_2 then,

A_2= \frac{A_1v_1 }{v_2}

So the cross sectional area of the water stream at a point 0.11 m below the faucet is

A_2= \frac{A_1v_1 }{v_2}

A_2= \frac{(2.4*10^{-4})(0.8)}{(1.67)}

A_2= 1.14*10^{-4} m2

Therefore the cross-sectional area of the water stream at a point 0.11 m below the faucet is 1.14*10^{-4} m2

8 0
3 years ago
Lactic acid is produced during low-moderate exercise <br> True <br> False
Marizza181 [45]
The answer to your question is true.
3 0
3 years ago
Read 2 more answers
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