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Ira Lisetskai [31]
3 years ago
12

Which measurement is a potential difference? A.115J B.115V C.115N D.115C

Physics
1 answer:
borishaifa [10]3 years ago
5 0

Answer:

B

Explanation:

Potential difference has a SI Unit of Volt and its symbol is <em>V</em>. Hence answer is <u>B</u>.

A is wrong as it has the unit Joule <em>(J)</em> which is the SI unit for energy.

C is wrong as it has the unit Newton <em>(N)</em> which is the SI unit for force.

D is wrong as it has the unit Coulomb <em>(C)</em> which is the SI unit of charge.

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lawyer [7]

I SAID don’t copy from internet but u did

Explanation:

5 0
2 years ago
Charge Q is distributed uniformly throughout the volume of an insulating sphere of radius R = 4.00 cm. At a distance of r = 8.00
Elena L [17]

Answer:

2.62898\times 10^{-6}\ C/m^3

1979.99974\ N/C

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

Q = Charge

r = Distance = 8 cm

R = Radius = 4 cm

Electric field is given by

E=\dfrac{kQ}{r^2}\\\Rightarrow Q=\dfrac{Er^2}{k}\\\Rightarrow E=\dfrac{990\times 0.08^2}{8.99\times 10^{9}}\\\Rightarrow Q=7.04783\times 10^{-10}\ C

Volume charge density is given by

\sigma=\dfrac{Q}{\dfrac{4}{3}\pi R^3}\\\Rightarrow \sigma=\dfrac{7.04783\times 10^{-10}}{\dfrac{4}{3}\pi (0.04)^3}\\\Rightarrow \sigma=2.62898\times 10^{-6}\ C/m^3

The volume charge density for the sphere is 2.62898\times 10^{-6}\ C/m^3

E=\dfrac{kQr}{R^3}\\\Rightarrow E=\dfrac{8.99\times 10^9\times 7.04783\times 10^{-10}\times 0.02}{0.04^3}\\\Rightarrow E=1979.99974\ N/C

The magnitude of the electric field is 1979.99974\ N/C

8 0
3 years ago
What is the identify atom shown
Alexus [3.1K]
There is no atom shown..
7 0
3 years ago
Who can help me for this question plz:(
Vanyuwa [196]
Force = mass x acceleration

15 = mass x 4

Mass = 15/4

Mass = 3.75 Kg
8 0
3 years ago
A box slides down a 31° ramp with an acceleration of 0.99 m/s2. Determine the coefficient of kinetic friction between the box an
tino4ka555 [31]

Answer:\mu=0.48

Explanation:

Given

inclination \theta =31^{\circ}

Acceleration of object=0.99 m/s^2

Now using FBD

mg\sin \theta -f_r=ma

mg\sin \theta -\mu mg\cos \theta =ma

a=g\sin \theta -\mu g\cos \theta

0.99=5.04-\mu 8.4

\mu 8.4=4.057

\mu =0.48

7 0
3 years ago
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