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3 years ago

Calculate the amount of formula units in 2.10 moles of MgCl₂

Chemistry

1 answer:

Eva8 [605]3 years ago

5 0

MgqI% = the formula and mass for H20 and that should be your answer for water

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Write down the structural formula for the monomer from which

Sati [7]

Answer:

Vinyl chloride is an organochloride with the formula H2C=CHCl that is also called vinyl chloride monomer (VCM) or chloroethene. This colorless compound is an important industrial chemical chiefly used to produce the polymer polyvinyl chloride (PVC).

Explanation:

7 0

2 years ago

Read 2 more answers

Given the equation representing a reversible reaction:

tester [92]

Answer:

- Acetic acid (CH₃COOH) and hydronium ion (H₃O⁺)

Explanation:

Hello,

In this case, based on the acid-base theory which states that acids are known as H⁺ donors, if we consider the direct reaction:

$CH_3COOH(aq) + H_2O \rightarrow CH_3COO^-(aq) + H_3O^+(aq)$

It is clear that the acetic acid is the first H⁺ donor as it losses one H⁺ to turn into the acetate ion. Moreover, if we consider the inverse reaction:

$CH_3COO^-(aq) + H_3O^+(aq)\rightarrow CH_3COOH(aq) + H_2O$

It is also clear that the hydronium ion is the second H⁺ donor as it losses one H⁺ to turn into water.

Best regards.

5 0

2 years ago

What is the concentration of an unknown Mg(OH)2 solution if it took an average of 15.4mL of

vova2212 [387]

Answer:

0.077M

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2HCl + Mg(OH)2 —> MgCl2 + 2H2O

From the balanced equation above,

The mole ratio of the acid (nA) = 2

The mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

Concentration of base Cb =...?

Volume of base (Vb) = 10mL

Concentration of acid (Ca) = 0.1M

Volume of acid (Va) = 15.4mL

Step 3:

Determination of the concentration of the base, Mg(OH)2.

The concentration of the base can be obtained as follow:

CaVa/CbVb = nA/nB

0.1 x 15.4 /Cb x 10 = 2/1

Cross multiply to express in linear form

Cb x 10 x 2 = 0.1 x 15.4

Divide both side by 10 x 2

Cb = (0.1 x 15.4) /(10 x 2)

Cb = 0.077M

Therefore, the concentration of the base, Mg(OH)2 is 0.077M

7 0

3 years ago

Certain compound contains 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen. It’s reality molecular mass is 176.0. Fi

erastovalidia [21]

Answer:

The answer to your question is:

Explanation:

Data

carbon 7.3% = 7.3g

hydrogen 4.5% = 4.5g

oxygen 36.4% = 36.4 g

nitrogen 31.8% = 31.8 g

Now

For carbon

12 g --------------------1 mol

7.3 g ------------- x

x = 7.3/12 = 0.608 mol

For hydrogen

1 g -------------------- 1 mol

4.5 g ------------------ x

x = 4.5 mol

For oxygen

16 g ------------------- 1 mol

36.4 g ---------------- x

x = 2.28 mol

For nitrogen

14 g ---------------- 1 mol

31.8 g --------------- x

x = 2.27 mol

Now divide by the lowest result, the is 0.608 from carbon

carbon 0.608/0.608 = 1

hydrogen 4.5/ 0.608 = 7.4

oxygen 2.28/0.608 = 3.75

nitrogen 2.27/0.608 = 3.73

Empirical formula = CH₇O₄N₄

6 0

2 years ago

If a 60-g object has a volume of 30 cm3, what is its density? 2 g/cm3 0.5 cm3/g 1800 g * cm3 none of the above

jasenka [17]

Answer : The density of an object is, $2g/cm^3$

Solution : Given,

Mass of an object = 60 g

Volume of an object = $30cm^3$

Formula used :

$\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}$

Now put all the given values in this formula, we get the density of an object.

$\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3$

Therefore, the density of an object is, $2g/cm^3$

6 0

2 years ago