Answer:
D. from a separate pool than is the control group.
Explanation:
in the picture the person answers is backwards but...
hope this helps have a nice day
Answer:
n=2.053
Explanation:
We will use Snell's Law defined as:
![n_{1}*Sin\theta_{1}=n_{2}*Sin\theta_{2}](https://tex.z-dn.net/?f=n_%7B1%7D%2ASin%5Ctheta_%7B1%7D%3Dn_%7B2%7D%2ASin%5Ctheta_%7B2%7D)
Where n values are indexes of refraction and
values are the angles in each medium. For vacuum, the index of refraction in n=1. With this we have enough information to state:
![1*Sin(39.9)=n_{2}*Sin(18.2)](https://tex.z-dn.net/?f=1%2ASin%2839.9%29%3Dn_%7B2%7D%2ASin%2818.2%29)
Solving for
yields:
![n_{2}=\frac{Sin(39.9)}{Sin(18.2)}=2.053](https://tex.z-dn.net/?f=n_%7B2%7D%3D%5Cfrac%7BSin%2839.9%29%7D%7BSin%2818.2%29%7D%3D2.053)
Remember to use degrees for trigonometric functions instead of radians!
The minimum average speed it must have in the second half of the event in order to qualify is 414.7 km/h.
<h3>
What is average speed?</h3>
The average speed of an object is the ratio of total distance traveled by the object to the total time of motion of the object.
<h3>Total time taken by the car during the entire race</h3>
time = distance/average speed
time = (1.41 km) / (278 km/h)
time = 0.0051 hr
The car travels the first half of the race, d (¹/₂ x 1410 m) at 210 km/h;
d = 705 m = 0.705 km
t1 = 0.705/210
t1 = 0.0034 hr
<h3>time for the second half</h3>
t2 = 0.0051 - 0.0034 hr
t2 = 0.0017 hr
<h3>minimum average speed of the second half</h3>
v = d/t
v = 0.705 km / 0.0017 hr
v = 414.7 km/hr
Thus, the minimum average speed it must have in the second half of the event in order to qualify is 414.7 km/h.
Learn more about average speed here: brainly.com/question/4931057
#SPJ1