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fgiga [73]
3 years ago
8

(25 pts) Estimate how much collector area and storage capacity would be required for an active solar hot-water system designed t

o supply the total needs for two four-person families, one living in Manchester, New Hampshire, where the latitude is 44+o north and the other in Albuquerque, New Mexico, at 35+o North. The heat capacity of water is about 4200 J/kgoC and the hot water supply temperature in both houses is 60oC (140oF). State and justify all additional assumptions made.
Physics
1 answer:
Aneli [31]3 years ago
6 0

Answer:

The required  total area is 1.48 m²

Explanation:

Given that,

Latitude = 44+° N

New Mexico,

Latitude= 35+° N

Heat capacity = 4200 J/Kg°C

Temperature = 60°C

Let us assume the input temperature 22°C

Estimate volume of water 100 ltr for 4 person.

We need to calculate the heat

Using formula of heat

H=mc_{p}\Delta T

H=mc_{p}(T_{f}-T_{i})

Put the value into the formula

H=100\times4200\times(60-22)

H=15960\ KJ...(I)

Let solar radiation for 6 hours/day.

We need to calculate the total energy per unit area

Using formula of energy

E=1000\times6\times3600\ J/m^2

E=21600\ KJ/m^2

Let the efficiency of collector is 50 %

Then,  the total energy per unit area will be

E=21600\times\dfrac{50}{100}

E=10800\ KJ/m^2....(II)

We need to calculate the required total area

Using equation (I) and (II)

A=\dfrac{H}{E}

Where, H = heat

E = total energy

Put the value into the formula

A=\dfrac{15960}{10800}

A=1.48\ m^2

Hence, The required  total area is 1.48 m²

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A spring that has a force constant of 1050 N/m is mounted vertically on the ground. A block of mass 1.95 kg is dropped from rest
aleksandrvk [35]

Answer:

25.2 cm

Explanation:

K = 1050 N/m

m = 1.95 kg

h = 1.75 m

By the conservation of energy, the potential energy of the block is converted into the potential energy stored in the spring

m g h = 1/2 x k x y^2

Where, y be the distance by which the spring is compressed.

1.95 x 9.8 x 1.75 = 1/2 x 1050 x y^2

33.44 = 525 x y^2

y = 0.252 m

y = 25.2 cm

8 0
3 years ago
A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
MrRissso [65]

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

5 0
3 years ago
A parallel-plate capacitor in air has a plate separation of 1.25 cm and a plate area of 25.0 cm2. The plates are charged to a po
Archy [21]

Answer:

(a) Since net charge remains same,after immersion Q is same

(b) I. 14.56pF ii. 3.05V

(c) ΔU = 5.204nJ

Explanation:

a)

C = kεA/d

k=1 for air

ε is 8.85x10-12F/m

A = .0025m2

d = .125m

C = 8.85x10-12x.0025/.125 = 1.77x10-13F = 0.177pF

Q = CV = .177pF * 244V = 43.188pC

Since net charge remains same,after immersion Q is same

b)

C = kεA/d, for distilled water k is approx. 80

Cwater = Cair x k

=0.177pF x 80 = 14.16pF

Q is same and C is changed V=Q/c holds. where Q is still 43.188pC and C is now 14.16pF, so V = 43.188pC/14.16pF = 3.05V

c) Change in energy: ΔU = Uwater - Uair

Uwater = Q2/2C = (43.188)2/2x.177pF = 5.27nJ

Uair = Q2/2C = (43.188)2/2x14.16pF = 0.066nJ

ΔU = 5.204nJ

6 0
3 years ago
If you were traveling 60 mph and not wearing a seatbelt and collided with a fixed object, how fast would you be traveling when y
Readme [11.4K]

Your speed when your car hits a fixed object is 60 mph.

The given parameters:

  • Your initial speed, v = 60 mph

<h3>What is relative velocity?</h3>

Relative velocity tells us how fast we are traveling from a fixed point or reference point.

  • When travel at 60 mph in a car, you are moving at the same rate with the car.
  • If you are not wearing a seat belt, when you hit a fixed object, you will move forward at the same rate as the car's speed.

Thus, we can conclude that your speed when your car hits a fixed object is 60 mph.

Learn more about relative velocity here: brainly.com/question/17228388

5 0
3 years ago
When you put water in a freezer it will turn into ice. This is because as the water _____ the movement of its particles ______.
Marta_Voda [28]
<span>A) cools down, slows down. When you put water in the freezer, it cools down and then the particles reduce their speed until they eventually form a solid by freezing.</span>
7 0
4 years ago
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