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ASHA 777 [7]
3 years ago
10

Which of the following best describes wind?

Physics
1 answer:
Afina-wow [57]3 years ago
5 0

Answer:

The answer is D the rising of warm air pushing down cool air.

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How does the science of heat transfer differ from the science of thermodynamics?
mariarad [96]

Answer:

The science of thermodynamics deals with the fundamental laws that guide how physical processes occur in relation with the energy transfer. When a system or process changes from one state of equilibrium to another, thermodynamics is interested with the amount of heat transfer during the process. On the other hand, the science of heat transfer is simply about the rate of heat and temperature distribution inside a system at a particular point in time.

Explanation:

3 0
3 years ago
You work at a retail store. Recently, paychecks have had errors and there have been many employee complaints. You have been assi
Nata [24]

Answer:

C,B,A

Explanation:

5 0
3 years ago
Read 2 more answers
A 100 kg bag of sand has a weight on 100 N. When dropped its acceleration is what?
Lyrx [107]
100N describes the weight of the sandbag, while 100kg is the mass of the sandbag.

To calculate acceleration, divide your weight by the mass, thus the accleration is:

100N/100kg = 1(m/s^2)
7 0
3 years ago
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Calculate the speed of a proton after it accelerates from rest through a potential difference of 350 V.
AVprozaik [17]

The speed of a proton after it accelerates from rest through a potential difference of 350 V is 25.86 \times 10^4 ~m/s.

Initial velocity of the proton u = 0

Given potential difference \Delta V = 350V

let's assume that the speed of the proton is v,

Since the proton is accelerating through a potential difference, proton's potential energy will change with time. The potential energy of a particle of charge q when accelerated with a potential difference \Delta V is,

    U = q \Delta V

Due to Work-Energy Theorem and Conservation of Energy - <em>If there is no non-conservative force acting on a particle then loss in Potential energy  P.E must be equal to gain in Kinetic Energy K.E</em> i.e

\Delta K = \Delta V

If the initial and final velocity of the proton is u and v respectively then,

change in Kinetic Energy  \implies  \Delta K = \frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}mv^2 - 0

change in Potential Energy \implies \Delta U = q\Delta V

from conservation of energy,

             v= \sqrt{\frac{2q\Delta V}{m}}

so,         v = \sqrt{\frac{2\times 350 \times 1.6\times 10^{-19}}{1.67 \times 10^{-27}}

                = 25.86 \times 10^4 ~m/s

To read more about the conservation of energy, please go to brainly.com/question/14668053

7 0
1 year ago
How high can a 40 N force move a load, when 395 J of work is done?
Juliette [100K]

Answer:

9.875

Explanation:

w=f×s

395=40×s

make s the subject of the formula

s=395/40

=9.875

7 0
3 years ago
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