Answer:
Δy = 7.1 cm
Explanation:
The center of mass of a body is defined
= 1 /M ∑
i
Where M is the total mass of the body, m mass of each part and ‘y’ height
Let's apply this equation to our case
We locate the reference system on the shoulders
The height of the arms is at its midpoint
y = -75/2 = 37.5 cm
With arms down
= 1/70 (63 y₀ - 3.5 37.5 - 3.5 37.5)
= 1/70 (63 y)₀ - 7 37.5)
With arms up
’= 1/70 (63 y₀ + 3.5 y + 3.5 y)
’= 1/70 (63y₀ + 7 35.5)
let's subtract the two equations
’ - = 1/70 2 (7 35.5)
Δy = ’ - = 2 7 35.5 / 70
ΔY = 7.1 cm
Answer:
The z-component of the force is 
Explanation:
From the question we are told that
The charge on the particle is 
The magnitude of the magnetic field is 
The velocity of the particle toward the x-direction is 
The velocity of the particle toward the y-direction is
The velocity of the particle toward the z-direction is
Generally the force on this particle is mathematically represented as
So we have
substituting values
 + [(5.58*10^{4}) (0.700)]\r y)](https://tex.z-dn.net/?f=%5C%3D%20F%20%20%3D%20%287.7%20%2A10%5E%7B-8%7D%29%28%5B%20%28-2.61%2A10%5E%7B4%7D%29%20%280.700%29%5D%28-%5Cr%20%20z%29%20%2B%20%5B%285.58%2A10%5E%7B4%7D%29%20%280.700%29%5D%5Cr%20y%29)
So the z-component of the force is
Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).
Answer:
B. the force of friction of the road on the tires
Explanation:
Unless the car engine is like jet engine, the main force that accelerates the car forward is the force of friction of the road on the tires, which is ultimately driven by the force of engine on the tires shaft. As the engine, and the shaft are part of the system, their interaction is internal. According to Newton laws of motion, the acceleration needs external force, in this case it's the friction of the road on the tires.
It shortens so that the tips reach faster
The electrical equivalent of one horsepower is 746 watts in the International System of Units (SI), and the heat equivalent is 2,545 BTU (British Thermal Units) per hour. Another unit of power is the metric horsepower, which equals 4,500 kilogram-metres per minute (32,549 foot-pounds per minute), or 0.9863 horsepower.
