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Ann [662]
3 years ago
7

Insoluble compounds in a chemical reaction are called?

Chemistry
1 answer:
Rzqust [24]3 years ago
8 0
They are called precipitates. 
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III. For the following four sections: If you are given the formula, name the
serious [3.7K]

Answer:

15.Potassium oxide

16.Calcium chloride

17.Aluminium sulphide

18.CaS

Explanation:

15.K is the chemical symbol of Potassium and generally the name of the non-metal at the end of a formula has the suffix '-ide' and since O is oxygen, the name becomes Potassium oxide.

16. The same applies here. Ca is Calcium and Cl is Chlorine but since its the non-metal at the end, it ends in -ide. So Calcium chloride.

17.The same applies here too. Al is Aluminium and S is Sulphur so Aluminium sulphide.

18. Calcium's symbol is Ca and that of Sulphur is S and that gives the formula CaS.

5 0
3 years ago
WILL MARK BRAINLIEST
Readme [11.4K]
Species are the smallest groups. A species consists of all the animals of the same type, who are able to breed and produce young of the same kind. For example, while any two great white sharks are in the same species, as are any two makos, great whites and makos are in different species (since they can't interbreed Answer :SPECIES
8 0
2 years ago
5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf
mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and pK_{a} is as follows.

               pH = pK_{a} + log \frac{base}{acid}

where,     pH = 7.4 and pK_{a} = 7.21

As here, we can use the pK_{a} nearest to the desired pH.

So,      7.4 = 7.21 + log \frac{base}{acid}

             0.19 = log \frac{base}{acid}

            \frac{base}{acid} = 1.55

1 mM phosphate buffer means [HPO_{4}] + [H_{2}PO_{4}] = 1 mM

Therefore, the two equations will be as follows.

           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

  [HPO_{4}] + [H_{2}PO_{4}] = 1 mM ........... (2)        

Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

                        2.55 [H_{2}PO_{4}] = 1 mM

                             [H_{2}PO_{4}] = 0.392 mM

Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

                          [HPO_{4}] = (1 - 0.392) mM

                              [HPO_{4}] = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0
3 years ago
It is composed of an alloy that is 90% Platinum and 10% Iridium; having a density of 21.186 g/cm3. What is the volume of the Sta
oksian1 [2.3K]
The alloy has a density of 21.186g/cc. So for a kilogram or 1000 grams/21.186 g/cc= 45.7 cc. So the answer is 45.7 cc of the allow to make up a kilogram which shows that the density of the allow can be used to calculate the volume of a larger mass ie the kilogram. 
7 0
3 years ago
6. Which of the following pH values would have the highest concentration of hydroxide ions? *
jeyben [28]

pH. 10 because it is strong base

4 0
3 years ago
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