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Natalija [7]
3 years ago
14

What is the pressure if 0.567 moles of gas occupy 4.5 liters at a temperature of 300.0 K?

Chemistry
1 answer:
kakasveta [241]3 years ago
3 0
The answer is D. Use the equation PV=nRT
P=(.567mol)(.0821)(300K)/4.5L
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Write equations to show whether the solubility of either of the following is affected by pH:(a) CuBr;
V125BC [204]

<u> </u><u>Increasing </u><u>pH will increase the </u><u>solubility </u><u>of the</u><u> CuBr.</u>

What is the solubility of water?

  • When a solute is dissolved in a solvent to give a homogeneous mixture, one has a solution.
  • Solubility is generally expressed as the number of grams of solute in one liter of saturated solution.
  • For example, solubility in water might be reported as 12 g/L at 25 oC.

2CuBr + 2OH-   ---> Cu2O(s)  + 2HBr(aq)

adding OH- to the CuBr also shifts the equilibrium to the right side therefore increasing pH will increase the solubility of the CuBr.

Learn more about solubility

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7 0
1 year ago
An unknown compound is processed using elemental analysis and found to contain 117.4g of platinum 28.91 carbon and 33.71g nitrog
dlinn [17]

Answer:

1 mole of platinum

Explanation:

To obtain the number of mole(s) of platinum present, we need to determine the empirical formula for the compound.

The empirical formula for the compound can be obtained as follow:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Divide by their molar mass

Pt = 117.4 / 195 = 0.602

C = 28.91 / 12 = 2.409

N = 33.71 / 14 = 2.408

Divide by the smallest

Pt = 0.602 / 0.602 = 1

C = 2.409 / 0.602 = 4

N = 2.408 / 0.602 = 4

The empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the formula of the compound (i.e Pt(CN)₄), we can see clearly that the compound contains 1 mole of platinum.

8 0
2 years ago
D) hydrogen and sulfur<br> Formed
mr Goodwill [35]

Answer:

At high temperatures or in the presence of catalysts, sulfur dioxide reacts with hydrogen sulfide to form elemental sulfur and water. This reaction is exploited in the Claus process, an important industrial method to dispose of hydrogen sulfide.

3 0
2 years ago
A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off at and the t
Mariulka [41]

Answer:

Therefore, the specific heat capacity of the iron is 0.567J/g.°C.

<em>Note: The question is incomplete. The complete question is given as follows:</em>

<em>A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm. </em>

<em> Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits</em>

Explanation:

Using the formula of heat, Q = mc∆T  

where Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)

When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water

mass of iron  = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C

∆T = 85.0 °C - 27.6 °C = 57.4 °C

mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C

∆T = 27.6°C - 23.0°C = 4.6 °C

Substituting the values above in the equation; Heat lost by Iron = Heat gained by water

59.1 g * c * 57.4 °C  = 100.0 g * 4.184 J/g.°C * 4.6 °C

c = 0.567 J/g.°C

Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.

5 0
2 years ago
What percentage of atoms in the entire universe are hydrogen atoms?
lisabon 2012 [21]
The percentage of atoms in the universe that are hydrogen are 90%
3 0
3 years ago
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