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Andrews [41]
4 years ago
12

What SI unit is used to measure the number of representative particles in a substance?

Chemistry
1 answer:
Galina-37 [17]4 years ago
4 0

Answer:

SI unit for number of representative particle is MOLE.

Explanation:

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How many orbitals are in Phosphorus
Viefleur [7K]

Answer:

3

three half-filled orbitals each capable of forming a single covalent Bond and an additional lone - pair of electrons

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3 years ago
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2. How much heat is released when 432g of water cools down from 710C to 180C?
nadya68 [22]
The heat released by the water when it cools down by a temperature difference AT

is Q = mC,AT

where

m=432 g is the mass of the water

C, = 4.18J/gºC

is the specific heat capacity of water

AT = 71°C -18°C = 530

is the decrease of temperature of the water

Plugging the numbers into the equation, we find

Q = (4329)(4.18J/9°C)(53°C) = 9.57. 104J

and this is the amount of heat released by the water.
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3 years ago
What is something that is not moving with respect to an observer that can be used to detect motion
larisa86 [58]

Answer:

Frame of reference

Explanation:

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3 years ago
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potassium, k, has an atomic number of 19 and an atomic mass of 39 how many electrons does a neutral atom of K have?
coldgirl [10]
A neutral atom of potassium has 19 electrons.
8 0
3 years ago
Calculate the final molarity of HCl the resulting solution when 5.56 mL of 4.108 M HCl is added to 4.44 mL of water.
puteri [66]

The final molarity of HCl is 2.284 M

We'll begin by listing what was given from the question. This is shown below:

Initial volume (V₁) = 5.56 mL

Initial Molarity (M₁) = 4.108 M

Final volume (V₂) = 5.56 + 4.44 = 10 mL

<h3>Final Molarity (M₂) =? </h3>

The final molarity of the HCl solution can be obtained by using the dilution formula as illustrated below:

<h3>M₁V₁ = M₂V₂</h3>

4.108 × 5.56 = M₂ × 10

22.84048 = M₂ × 10

Divide both side by 10

M₂ = 22.84048 / 10

<h3>M₂ = 2.284 M</h3>

Therefore, final molarity of the HCl solution is 2.284 M.

Learn more: brainly.com/question/6103588

5 0
3 years ago
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