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4 years ago

What SI unit is used to measure the number of representative particles in a substance?

Chemistry

1 answer:

Galina-37 [17]4 years ago

4 0

Answer:

SI unit for number of representative particle is MOLE.

Explanation:

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154 pm is greater than 7.7 x10^-9 A. True B. False

Nesterboy [21]

The answer is false.

7 0

3 years ago

2 reasons for chemical reactivity of nitrogen

erma4kov [3.2K]

Answer:

Due to presence of a triple bond between the two N−atoms, the bond dissociation enthalpy (941.4 kJ mol

−1

) is very high. Hence, N

is the least reactive.

6 0

3 years ago

Patient added a 17-g measured dose of polyethylene glycol 3350 (MIRALAX) to 180 mL of water to use as a laxative. If the volume

Sergio [31]

Answer: Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

Specific gravity of mixture = 1.01

Explanation:

The specific gravity of an object or substance is the ratio of the density of that object or substance to that of a reference substance usually water.

Specific gravity = density of substance/density of water

The density of a substance is the ratio of the mass of that substance to is volume.

Density = Mass/volume

Density of water 1.00 g/mL,

Apparent density of ethylene glycol 3350 = mass/volume

volume of ethylene glycol = volume of mixture - volume of water

volume of ethylene glycol = 195.6 - 180) = 15.6mL

Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

mass of water = density of water * volume of water

mass of water = 1.00g/mL * 180mL = 180 g

Mass of solution = mass of substance + mass of water = (17 + 180)g = 197g

Density of mixture = mass of mixture / volume of mixture

Density of mixture = 197 g / 195.6 mL = 1.01 g/mL

specific gravity of mixture = density of mixture / density of water

specific gravity of mixture = 1.01g/mL / 1.00g/mL

specific gravity of mixture = 1.01

8 0

4 years ago

How many grams of water can be formed from the reaction of 8.76 grams of H2 with 10.5 liters of O2 (at STP) according to the bal

Kisachek [45]

Answer:

16.9g of H₂O can be formed

Explanation:

Based on the chemical reaction, 2 moles of H₂ react per mole of O₂. To anser this question we must find limiting reactant converting the mass and volume of each reactant to moles:

Moles H₂ -Molar mass: 2.016g/mol-:

8.76g * (1mol / 2.016g) = 4.345 moles

Moles O₂:

PV = nRT

PV/RT = n

P = 1atm at STP

V = 10.5L

R = 0.082atmL/molK

T = 273.15K at STP

n = 1atm*10.5L / 0.082atmL/molK*273.15K

n = 0.469 moles of oxygen

For a complete reaction of 4.345 moles moles of hydrogen are required:

4.345 moles H2 * (1mol O2 / 2mol H2) = 2.173 moles of O2 are required. As there are just 0.469 moles, Oxygen is limiting reactant

Now, 1 mole of O2 produce 2 moles of H2O. 0.469 moles will produce:

0.469 moles O₂ * (2 moles H₂O / 1mol O₂) = 0.938 moles H₂O.

The mass is -Molar mas H₂O = 18.01g/mol-:

0.938 moles * (18.01g/mol) =

<h3>16.9g of H₂O can be formed</h3>

8 0

3 years ago

Name three sources of atmospheric carbon dioxide.

quester [9]

The answer is decomposition, ocean release and respiration. hope this helps u :D

4 0

3 years ago