There will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.There will be needed mL of
Why?
In order to calculate how many milliliters are needed to obtain 16.1 grams of the salt given its concentration, we first need to find its chemical formula which is the following:

Now that we know the chemical formula of the substance, we need to find its molecular mass. We can do it by the following way:

We have that the molecular mass of the substance will be:

Therefore, knowing the molecular mass of the substance, we need to calculate how many mols represents 16.1 grams of the same substance, we can do it by the following way:


Finally, if we need to calculate how many milliliters are needed, we need to use the following formula:


Now, substituting and calculating, we have:

Henc, there will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.
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Answer : the statement that is true about the atom is It is present in the second group of the periodic table.
Explanation :
The Lewis dot model shows the number of valence electrons present in the atom.
Since the given metal has 2 dots, it indicates that the metal atom must have 2 electrons in its outermost shell.
Therefore option 2 : It has two electrons in the innermost energy level, is wrong because it contains 2 electrons in the outermost energy level
Option 1 : It is most likely to form covalent bonds is also wrong because a metal atom always forms ionic bond
Option 3 : It requires six other atoms to form a stable compound, is also wrong as the metal can form a stable compound by donating its 2 electrons to a non metal.
On periodic table, representative elements are arranged in groups based on their valence electrons. Therefore by knowing the outermost electrons, we can predict the group in which the element can be categorized.
Since the given metal atom contains 2 electrons, it must be present is second group.
Therefore the statement that is true about the atom is It is present in the second group of the periodic table.
1740 g because the molar mass is 133.33g/mol, mulitplied by 11.37 mol = 1743.36. 1740 is closest and it may be a bit off depending on how many sig figs are used for the molar mass. So 1740g