Answer:
146g
Explanation:
We're assuming the reaction is occurring with excess chloride. First convert hydrogen mass to moles using molar mass - you need to work with numbers for these sorts of questions:
n = m / MM
n = 2g / 1g/mol
n = 2mol
Now use your stoich ratio to find how many moles of HCL are produced. There are 2 moles of HCl produced for every 1 mole of H2 reacted so:
x HCl / 2 mol H2 = 2 HCl / 1 H2
x = 4mol HCl
Now convert this back into mass using the molar mass of HCl:
m = n x MM
m = 4mol x 36.5g/mol
m = 146g
Answer:
Second Ionization energy
Explanation:
Let us write the reaction equation properly:
Ca⁺ → Ca²⁺ + e⁻
In the reaction above, we see that calcium goes from a single charge to being doubly charged by losing an electron.
Different atoms binds their valence electrons with different amount of energy. We must supply enough energy to remove the most losely held electrons in an atom. This amount of energy required is called the ionization energy.
The first ionization energy removes the outermost electron and makes the atom to become an ion.
Temperature is the measurement of thermal energy
Answer:
152.4 g of O₂ are consumed.
Explanation:
We start from the combustion reaction:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
We convert the mass of propane to moles:
41.9 g . 1mol /44g = 0.952 moles
Ratio is 1:5. 1 mol of propane consumes 5 moles of oxygen at propane combustion
Then, 0.952 moles may consume (0.952 . 5) /1 = 4.76 moles.
We convert moles to mass → 4.76 mol . 32g/mol = 152.4 g
Answer:
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Explanation:
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