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Sholpan [36]
4 years ago
12

Determine the concentration of h 3 o + to the correct number of significant figures in a solution with each ph. describe how the

se calculations show the relationship between the number of digits to the right of the decimal place in ph and the number of significant figures in concentration. ph = 2.50 ph = 2.51 ph = 2.52
Chemistry
1 answer:
kvasek [131]4 years ago
6 0

To calculate the concentration of H3O+


1- when PH = 2.5 :


The explanation:


we are going to use this formula:


PH = - ㏒[H3O+]


and we here have PH = 2.5 so, by substitution:


2.5 = -㏒ [H3O+]


∴ [H3O+] = 0.00316 ≈ 0.003


2- when PH = 2.51 :


The explanation:


we are going to use this formula:


PH = - ㏒[H3O+]


when here we have PH = 2.51 so, by substitution:


2.51 = - ㏒[H3O+]


∴[H3O+] = 0.00309 ≈ 0.003


3- when PH = 2.52 :


The explanation:


we are going to use this formula:


PH = - ㏒[H3O+]


when here we have PH =2.52 so, by substitution:


2.52 = -㏒[H3O+]


∴[H3O+] = 0.00301 ≈ 0.003


we can see that when the the number of digits to the right of the decimal place in ph increase, the number of significant figures in concentration decrease.


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What is the pOH of a solution of HNO3 that has [OH-] = 9.50 10-9 M?
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What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
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Answer:

1.2 mL

Explanation:

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Cross multiply

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Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

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