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meriva
3 years ago
8

Help ASAP PLEASE !!!!!!

Chemistry
1 answer:
expeople1 [14]3 years ago
4 0
The answer would be B.  Increased fertility downstream. Hope this helps. It's been a while since iv'e done the test, but I think this is the correct answer.

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9. Which one of the following is not a potential effect of global warming?
valentina_108 [34]

Answer:

D. Increase in UV radiation​

Explanation:

I hope it helps. brainliest pls

5 0
2 years ago
5. __NH3 + __O2 >>>>>__ NO +__ H20
inn [45]
2 NH3+ 2 O2 —> 2 NO+ 3 H2O
5 0
3 years ago
Cocaine selectively blocks na+ (sodium) channels, which is the mechanism that leads to
anzhelika [568]
Cocaine selectively blocks sodium channels which is the mechanism that leads to local anesthetic effects. 
Voltage gated sodium channels play very important roles in the body as they are responsible for action initiation and propagation in excitable cells, such as nerves, muscles and neuroendocrine cells. Like other sodium ion channels blockers such as lidocaine, Cocaine selectively blocks sodium ion channels which denies entry of sodium ions in the cell, thus leading to local anesthetic effects. 
5 0
3 years ago
Write the equilibrium constant expression for the reaction below.
kodGreya [7K]

Answer:

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

Explanation:

The equilibrium constant indicates the % of the yield reaction and can shows where the reaction is going to be equilibrated.

It works with molar concentrations on the equilibrium and it does not consider the solids compounds

Kc also can be modified by the time of the reaction.

This reaction is:

CS₂ (g) + 4 H₂O(g) ⇌ CH₄ (g) + 2H₂S (g)

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

8 0
3 years ago
A 275 g sample of a metal requires 10.75 kJ to change its temperature from 21.2 oC to its melting temperature, 327.5 oC. What is
Vlada [557]

Answer:

c=0.127\ J/g^{\circ} C

Explanation:

Given that,

Mass of the sample, m = 275 g

It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.

We need to find the specific heat of the metal. The heat required by a metal sample is given by :

Q=mc\Delta T

c is specific heat of the metal

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C

So, the specific heat of metal is 0.127\ J/g^{\circ} C.

4 0
2 years ago
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