We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.
The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.
Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, moles = 0.375 moles of nitrogen is required.
Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.
Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.
Answer:
If this is that MC question then the answer is D.
Explanation:
The correct answer is D. The energy needed for a chemical reaction is called the activation energy. This energy is to be present in order for the reaction to happen. This can be achieved by supplying or releasing heat from a system of reactants. This can achieved faster by using a catalyst.
-1 charge = the atom has gained one electron
9+1=10
Radon gas causes cancer and is highly radioactive. Its a byproduct of radioactive decay from Uranium and is hard to impossible to detect through smell, or sight.